Suppose a ball falls from rest from height h, then by equation of motion:
h=1/2*g*t2 . and for horizontal motion, x=vx*t. put value of t in first equation:
h=1/2*g*x2/v2, or
x=(h*2*v2/g)1/2. or
x=k*h1/2, so
x1/h11/2=x2/h21/2;
put the values,
x1=601/2*76/44.11/2;
Work with calculator now......
Range of a projectileThe path of this projectile launched from a height y0 has a range d.In physics, a projectile launched with specific initial conditions in a uniform gravity field will have a predictable range. As in Trajectory of a projectile, we will use:g: the gravitational acceleration-usually taken to be 9.80 m/s2 (32 f/s2) near the Earth's surfaceθ: the angle at which the projectile is launchedv: the velocity at which the projectile is launchedy0: the initial height of the projectiled: the total horizontal distance travelled by the projectileWhen neglecting air resistance, the range of a projectile will beIf (y0) is taken to be zero, meaning the object is being launched on flat ground, the range of the projectile will then simplify toso to increase the range θ shoud vary from 0 to 45 and after 45 it starts decreasing.
It reaches a maximum height of 10 to 20 feet
You cannot. You need to know either the initial speed or angle of projection (A).
It is not precisely clear what you are asking, but perhaps you are looking for the word "Trajectory," which refers to the path a projectile takes.
Kinetic energy is dependent on which point you are talking about. When it is about to be dropped, kinetic energy is zero. When it reaches almost hits the ground, there is maximum kinetic energy.
If a projectile takes 8 seconds to reach its maximum height, it will take another 8 seconds to return to its original elevation. Presuming it is lauched from flat ground and returns to the ground, its total time in flight would be 16 seconds. If it is launched from a hill, or at a hill, more information would be needed.
You can't unless you know gravity and air pressure as well.
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
45 degrees.
When it's at its maximum height its speed will be zero.
Range of a projectileThe path of this projectile launched from a height y0 has a range d.In physics, a projectile launched with specific initial conditions in a uniform gravity field will have a predictable range. As in Trajectory of a projectile, we will use:g: the gravitational acceleration-usually taken to be 9.80 m/s2 (32 f/s2) near the Earth's surfaceθ: the angle at which the projectile is launchedv: the velocity at which the projectile is launchedy0: the initial height of the projectiled: the total horizontal distance travelled by the projectileWhen neglecting air resistance, the range of a projectile will beIf (y0) is taken to be zero, meaning the object is being launched on flat ground, the range of the projectile will then simplify toso to increase the range θ shoud vary from 0 to 45 and after 45 it starts decreasing.
The value of the vertical speed at the highest point of the projectile's trajectory is the lowest speed at the maximum height reached.
It reaches a maximum height of 10 to 20 feet
15.42 degrees
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
It will take one year for the tree to reach half its maximum height. Since the tree doubles in height each year, it will be at half its maximum height the year before it reaches its full height.
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)