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Answer: 50% Tall : 50% Short
1/2 Tall 1/2 Short.
75% there will be TT, Tt, Tt, and tt. tt is going to be short. This means that 3/4 will be tall. 3/4 is 75%
3 : 1 ( since the given situation of segregating genotypes TT Tt Tt tt comes under monohybrid genetic combination, it will show 3 tall plants and 1 dwarf plant because gene T is dominant over t.
yes becasue the color changes and it doset mean it's not almost exactly the same as a black or even a purple fly when its crossed with another fly you get (tt) (TT) (tT) AND (Tt)
genotype of the parents - parents will be heterozygous dominant. e.g. take the example of Mendel's pea cross. if parent is heterozygous dominant then the genotype will be Tt and Tt now if you will do a cross then the result you will get is this - Tt X Tt result - TT, Tt, Tt, tt it gives a 3 : 1 ratio i.e. three tall and one dwarf. Source: "tumul v" yahoo.answers
Using a punnett square you get the results of TT, TT, Tt, Tt. Key= T-tall t-short It's going to be tall but can have different genotypes
If tall (T) is dominant and small (t) is recessive, and both are homozygous, they would all be tall. (100% tall, heterozygous.) If the tall is heterozygous, it would be 50% tall heterozygous and 50% short heterozygous.
Tt, tt -- novanet :)
A cross between members of the F1 generation (Tt x Tt), results in the genotypic ratio of 1TT:2Tt:1tt genotypes in the F2 generation. Because the tall allele is dominant, the phenotypic ratio would be 3 tall:1 short in the F2 generation.
If the two parent pea plants have Tt traits, they will create TT, Tt, Tt, tt. 1 TT - homozygous dominant, 2 Tt - heterozygous, and 1 tt - homozygous recessive.
Tt, tt -- novanet :)