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GIven m1v1 = m2 v2 -----------------(1)

Needed m1v12 / m2v22 = v1 / v2

But right from (1) v1 / v2 = m2 / m1

Given m1 = 1 g and m2 = 4 g

So required ratio of KE = 4:1

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Q: What is the ratio of kinetic energies between two particles of masses 1g and 4g moving with equal linear momentum?
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