in my chem 201 lab we found this to be 1.099 kJ/ mol. I am in fact looking for the accepted value as well. So i assume my result is near the accepted i hope. If anyone knows throw down your info.
Hydrochloric acid and the base sodium hydroxide react to form the salt sodium chloride and water.
HCl + NaOH --> NaCl + H2O
acid + base --> salt + water
The neutralization reaction of sodium hydroxide and hydrochloric acid will form sodium chloride (common salt) and water. NaOH +HCl --> NaCl+ H2O
sodium chloride"
Neutralization
It is an acid-base reaction and will form water and sodium chloride.
Neutralization with a base (possible a basic waste) as sodium hydroxide or ammonium hydroxide, etc.
The neutralization reaction of sodium hydroxide and hydrochloric acid will form sodium chloride (common salt) and water. NaOH +HCl --> NaCl+ H2O
sodium chloride"
Neutralization
It is an acid-base reaction and will form water and sodium chloride.
Sodium hydroxide + Hydrochloric acid ----> Sodium chloride + Water It is a neutralization reaction and is also exothermic. Products are Sodium chloride and water.
Neutralization with a base (possible a basic waste) as sodium hydroxide or ammonium hydroxide, etc.
Neutralization reaction occurs.
Neutralization reaction: as an example the reaction between hydrochloric acid and sodium hydroxide.
Neutralization with a base (possible a basic waste) as sodium hydroxide or ammonium hydroxide, etc.
Hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH) in a neutralization reaction. This is an acid + base, so you end up with a salt (NaCl - sodium chloride) plus water (H2O).HCl + NaOH ==> NaCl + H2O
NaOH(aq) + HCL(aq) = NaCl(aq)l + H2O(l)
It is an example of neutralization reaction:NaOH + HCl = NaCl + H2O