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Oxymercuration. Add Hg(OAc)2 to make any alkene a secondary alcohol or make the OH go on the most substituted Carbon. a.k.a. Markarvnikov addition of OH.
C3H8 is the chemical formula of propane (hydrocarbon, alkane).
HBR doesn't react with Propane, but it does with Propene. The product is either 1-bromo propane(minor product) or 2-bromo propane(major product). To determine which product will be the major product, use the Markovnikov's rule.
An addition reaction, specifically it is called hydrogenation.
reaction of 2-chloro.2-methyl propane with sodium metal
In order to convert propene to propane you must break the C=C double bond. The simplist way to do this is with a Lindlar catalyst (eg. H2,Pd). This reagent will break the double bond, giving you propane. The same reagent will also work if you need to break and triple bond and make it a double bond.
Propane is C3H8.Propene is C3H6.
Oxymercuration. Add Hg(OAc)2 to make any alkene a secondary alcohol or make the OH go on the most substituted Carbon. a.k.a. Markarvnikov addition of OH.
propene or cyclopropene dependant on bonding
wood, leaves, paper, wax, hydrogen gas, ethanol, methane, propane, propene, benzene (Propane and and propene are two different substances- propene has an extra double bond.)
React with alcoholic KOH (dehydrohalogenation) to give 1-propene, followed by treatment with HCl (electrophilic addition).
Propane is the common name---I have never heard of it called anything else. Natural gas contains propane, but there is typically more methane and ethane in natural gas than there is propane.
when 2 chlori propane is reacted in presence of ethanolic koH it form propene .
Propene + Br2 + hv ==> 3-Bromo-1-propene (free radical halogenation - allylic position is halogenated only)3-bromo-1-propene + OsO4 ==> 1,2 dihydroxy-3-bromo propane (or, you can also use MCPBA to create the epoxide and open it with mild acid or base, or you can use Br2 and H2O to create the halohydrin... lots of options here)1,2 dihydroxy-3-bromo propane + NaOH ==> 1,2,3 trihydroxy propane (glycerin aka glycerol)
The answer is: 4,2 g propene and 1,8 g water; it is a dehydration reaction.
A common mechanism is the hydrogenation of a double bond, which would produce propane
HCl