How would you convert 2 chloropropane to propene?

Answer 1

when 2 chlori propane is reacted in presence of ethanolic koH it form propene .

Answer 2

By reaction with alcoholic KOH (the reaction will be an example of dehydrohalogenation)

Answer 3

method 1: propyne + H2 on Pt catalyst => propane. then do free radical halogenation with Br2, which will prefer to add to the most substituted carbon atom, giving 2-bromopropane

method 2: propyne + H2 on poisoned catalyst (ex Lindlar's) => propene. next do oxymecuration/demercuration (which tends to give you the more substituted alcohol) to yield isopropanol. next, brominate with HBr or P + Br2 or PBr3, etc to yield 2-bromopropane.

Answer 4

1-bromopropane is CH2BrCH2CH3. The Br is removed as HBr molecule by adding alcoholic KOH as the reagent. This would result in 1-propene CH2=CHCH3. Then hydrobromination is done by adding HBr. H would add to the terminal C according to Markovnikov's rule. This would give 2-bromopropane CH3CHBrCH3.

Answer 5

React 2-chloro propane with NaOHaq. the produced 2-propanol when reacts with HBr you may get the 2-bromo propane.

1. CH3-CH(Cl)-CH3 + NaOH -----> CH3-CH(OH)-CH3 + NaCl

2. CH3-CH(OH)-CH3 + HBr ------> CH3-CH(Br)-CH3 + H2O

Answer 6

The Dehydrohaogenation of 1-bromo propane with alcoholic KOH gives propene which on again hydrohalogenation with HBr gives 2-bromo propane due to Markonikove's rule for addition.

Answer 7

1st convert 1 bromoropane to its corresponding grignard reagent the treat with water athen we get bromane we treat it with HBr to and by markonikoff rule we get 2-bromo propane

Answer 8

Electrophilic addition reaction

Answer 9

Answer