first treat the PROPENE with HBR to form 2-bromopropane. And then treat it with Na in the presence of dry ether to get 2,3-dimethyl butane
Butane has 2 isomers:CH3CH2CH2CH3 - butaneCH3CH(CH3)CH3 - 2-methylpropane (or isobutane)
2-hexanone3-hexanone2-methyl-3-pentanone3-methyl-2-pentanone4-methyl-2-pentanone3,3-dimethyl-2-butanone
The major product from the treatment of propene with HCl is 2-chloropropane. The HCl adds across the double bond of propene to form a secondary alkyl halide.
To determine the amount of water and propene that can be formed, we first need to write out the balanced chemical equation for the reaction of 2-propanol (C3H8O) to form water (H2O) and propene (C3H6): C3H8O -> C3H6 + H2O Next, calculate the molar mass of 2-propanol (60.1 g/mol) and the molar masses of water (18.0 g/mol) and propene (42.1 g/mol). Then, use stoichiometry to convert the mass of 2-propanol to moles, and from there determine the amount of water and propene that can be formed.
The reaction in which propene is converted to 2-chloropropane is an electrophilic addition reaction with hydrogen chloride (HCl) in the presence of a catalyst like a peroxide. The double bond in propene acts as a nucleophile, attacking the electrophilic hydrogen of HCl to form 2-chloropropane.
2-chloropropane to 2,3-dimethyl butane
Butane has 2 isomers:CH3CH2CH2CH3 - butaneCH3CH(CH3)CH3 - 2-methylpropane (or isobutane)
2-hexanone3-hexanone2-methyl-3-pentanone3-methyl-2-pentanone4-methyl-2-pentanone3,3-dimethyl-2-butanone
The major product from the treatment of propene with HCl is 2-chloropropane. The HCl adds across the double bond of propene to form a secondary alkyl halide.
Propene can be converted to propan-2-ol through a two-step process. First, propene is reacted with water in the presence of a strong acid catalyst to form propan-2-ol. This reaction is known as hydration of propene. Second, the intermediate product formed from this reaction undergoes a dehydration reaction to yield propan-2-ol.
To determine the amount of water and propene that can be formed, we first need to write out the balanced chemical equation for the reaction of 2-propanol (C3H8O) to form water (H2O) and propene (C3H6): C3H8O -> C3H6 + H2O Next, calculate the molar mass of 2-propanol (60.1 g/mol) and the molar masses of water (18.0 g/mol) and propene (42.1 g/mol). Then, use stoichiometry to convert the mass of 2-propanol to moles, and from there determine the amount of water and propene that can be formed.
S(CH3)2 is the formula for Dimethyl Sulfide analogous to Dimethyl ether
The reaction in which propene is converted to 2-chloropropane is an electrophilic addition reaction with hydrogen chloride (HCl) in the presence of a catalyst like a peroxide. The double bond in propene acts as a nucleophile, attacking the electrophilic hydrogen of HCl to form 2-chloropropane.
The oxidation of 3,3-dimethyl-2-butanol would yield a ketone, specifically 3,3-dimethyl-2-butanone. This reaction involves the conversion of the alcohol functional group to a ketone via loss of hydrogen atoms.
Propene can be converted into 1-bromopropane by reacting it with hydrobromic acid in the presence of a peroxide initiator. The peroxide initiates a free radical chain reaction that leads to bromination of the propene. To form 2-bromopropane, propene can be treated with elemental bromine or N-bromosuccinimide (NBS) in the presence of light or heat, which leads to anti-Markovnikov addition of bromine across the alkene double bond.
The formula is 2 x C2H5 = C4H10. :)
Propene formula CH3-CH=CH2 in which 2 elements Carbon and Hydrogen are combined, sharing 9 covalent electron bonds