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The focal length of a convex mirror is half of its radius of curvature.
More the curvature of the eye lens, lesser the focal length is. Lesser the curvature, greater the focal length is
the curvature mirror the emage of the mirror is virtual
Not at all. The focal length is determined by the curvature of the surfaces.
NO it cannot be. Because radius of curvature is given by the expression R = 2 f
R = 2f
The focal length of a concave mirror is about equal to half of its radius of curvature.
The focal length of a convex mirror is half of its radius of curvature.
The Center of curvature is 2 times the focal length. By the way this is a physics question.
More the curvature of the eye lens, lesser the focal length is. Lesser the curvature, greater the focal length is
f=|-R/2|
radius of curvature = 2Focal length
the curvature mirror the emage of the mirror is virtual
zooming in decreases the focal length
The focal length (a.k.a focus) is exactly half the length of the centre of curvature. ie. F = 1/2 C
Not at all. The focal length is determined by the curvature of the surfaces.
yes