The height where from the body is dropped ie h is given as
h = v2 / 2g
and h = (1/2) g t2
v is the final velocity and t is time of falling
g = acceleration due to gravity
Velocity= sqrt(2(distance*gravity))
the greatest velocity a falling object reaches is terminal velocity
the greatest velocity a falling object reaches is terminal velocity
A falling object accelerates at a rate of 9.8 m/s2. That means that for every second that it is falling, its velocity increases by 9.8 m/s. The higher that the object is falling from, the longer it will have to speed up, thus the higher its velocity upon impact will be. (This is assuming that it does not reach terminal velocity, the velocity at which an object can no longer accelerate because it is travelling so fast that the drag force (air resistance) is equal to the force of gravity.)
The object opposes the air and while falling of the object the initial velocity will become zero , and the final velocity will have some value's this is how air will resist the velocity of falling object ...........
yes it does. u can calculate the final velocity of the falling object with the following eqn: initial potential energy= final kinetic energy or mgh = 1/2mv2 where m=mass, h = height,v=final velocity
The fastest velocity a falling object can reach is called its terminal velocity. This happens when the force of air resistance is equal to the downwards force of weight (gravity), so the object is in equilibrium, and thus reaches a constant velocity.
Terminal velocity.
Velocity increases
terminal velocity
When THE FRICTION BETWEEN THE OBJECT AND THE ATMOSPHEREequals the force of gravity on a falling object the object reaches terminal velocity.
Velocity increases but not infinitely.