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4X2+X3+3X+7Y+2X3 can only be simplified to 3X3+4X2+3X+7Y, because X3 and 2X3 are the only like terms.
Fifth degree - the highest power of x that appears.
If that's + 4x2, the answer is 2x(x2 + 2x - 4)
(x4 - 2x3 + 2x2 + x + 4) / (x2 + x + 1)You can work this out using long division:x2 - 3x + 4___________________________x2 + x + 1 ) x4 - 2x3 + 2x2 + x + 4x4 + x3 + x2-3x3 + x2 + x-3x3 - 3x2 - 3x4x2 + 4x + 44x2 + 4x + 40Râˆ´ x4 - 2x3 + 2x2 + x + 4 = (x2 + x + 1)(x2 - 3x + 4)
4x2 = -12x, divide both sides by 4x: x = -3
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
2x4 - 9x3 + 13x2 - 15x + 9 = 2x4 - 6x3 - 3x3 + 9x2 + 4x2 - 12x - 3x + 9 = 2x3(x - 3) - 3x2(x - 3) + 4x(x - 3) - 3(x - 3) = (x - 3)*(2x3 - 3x2 + 4x - 3) So the quotient is (2x3 - 3x2 + 4x - 3) and the remainder is 0.
4x2 + 6x - 3 (with no remainder)
4x2 plus 3=11
(x-2)*(2x2+5x-3) Multiply out the brackets term by term taking care with the minus terms:- 2x3-4x2+5x2-10x-3x+6 Collect like terms:- Answer: 2x3+x2-13x+6
4x2 + x2 = 8 + x2
5, if the numbers after the "x" are supposed to be powers
Divide all terms by 4:- x2+7x+12 = (x+3)(x+4) when factored
4x2 + 12x + 5 = (2x + 1)(2x + 5).
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
x3 + 4x2 + x + 4 = (x + 4)(x2 + 1)
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
(6x^5-4x^2)+(2x^3-3) = 6x^5-4x^2+2x^3-3 The grestest exponent is 5, which is the degree of the above expression.
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified