2.567 ohms
Calculated using: http://www.cirris.com/learning-center/calculators/133-wire-resistance-calculator-table
A #8 copper wire with an insulation factor of 75 or 90 degrees C has a rating of 45 amps. The load amperage and voltage must be stated to give a voltage drop calculation. <<>> The answer requires more information i.e. what is the voltage how far do you want to run the #8 wire? #8 wire is limited to carrying 24 amps per the National Electrical Code is it's carrying power for transmission from one point to another. It also exhibits a resistance of .682 ohms per 1000 feet so this resistance relates to voltage drop at the end of a piece of wire. Normally a run of 300 to 500 feet is no problem as long as you are prepared to have a little less current at the end of the wire. The way the wire is run also has a great deal to do with the distance. If it's placed in a raceway (read conduit) by itself or with other conductors then the wire ampacity must be derated. As you see, there's a lot to it. The best rule of thumb is that is you need 20 amps at a 1000 feet, use the next size wire or AWG #6.
100 sq' divide by 3 = 33.3 sq yards. man we have some wiki math problems.
The answer will depend on 24 WHAT!
8 yards are in 24 feet24 feet = 8 yards24 feet is 8 yards.
24 FEET = 8 YARDS
If the wires are of identical materials, the 26 guage wire has more (higher) resistance.
It is a true statement.
100 square feet.
24*4=100. So, the perimeter is 100 feet. Or, P=100 ft
Each length of wire needs to be 179 feet long - X 3 = 537 FEET OF WIRE NEEDED.
Answer Usually it is square feet. Six ounces per every 100 square feet. So take 28 x 24 and that equals 672 square feet. Then you divide 672 by 100 and that equals 6.72. Take 6.72 x 6 and that equals 40.32. This means that you need 40.32 ounces for this area. Good luck.
24 x 24 = 576 square feet.
There are: 24*24 = 576 square feet
Yes, a #10 wire will carry 30 amps for 30 feet. If the load is rated as continuous then the wire will have to be derated to 80% capacity which will leave you with 24 workable amps. If the load demands currents higher that 24 amps then you will have to go to the next wire size up which is a #8 which is rated at 45 amps.
14 x 24 = 336 square feet.
Per cent means "of 100". So 24 of 100 is 24 per cent.
A #8 copper wire with an insulation factor of 75 or 90 degrees C has a rating of 45 amps. The load amperage and voltage must be stated to give a voltage drop calculation. <<>> The answer requires more information i.e. what is the voltage how far do you want to run the #8 wire? #8 wire is limited to carrying 24 amps per the National Electrical Code is it's carrying power for transmission from one point to another. It also exhibits a resistance of .682 ohms per 1000 feet so this resistance relates to voltage drop at the end of a piece of wire. Normally a run of 300 to 500 feet is no problem as long as you are prepared to have a little less current at the end of the wire. The way the wire is run also has a great deal to do with the distance. If it's placed in a raceway (read conduit) by itself or with other conductors then the wire ampacity must be derated. As you see, there's a lot to it. The best rule of thumb is that is you need 20 amps at a 1000 feet, use the next size wire or AWG #6.