If both parent are carriers there is a 1 in 4 chance the child will have CF. and a 50% chance they will be a carrier them self.
Zero. Cystic fibrosis is an autosomal recessive disease. This means that both parents must carry a mutated gene and have a 1 in 4 (25%) chance of having a child with CF.
because 95% of men with cystic fibrosis are sterile
If both parents are carriers then the child has a 25% chance of having cystic fibrosis. If one parent has CF and the other the other was just a carrier then the child has a 50% chance of having CF. If one parent has CF and the other has two normal genes then there is no chance of the child having CF. If one parent is a carrier and the other has two normal genes then there is no chance of the child having CF. If both parents have CF then there is a 100% chance that the child will also have CF.
If only one person is a carrier of cystic fibrosis than there is no chance of having a child with it. Both parents have to be carriers and even then there is only a 25% chance. If only one carries than there is a 50% chance that their children will carry but will not have cystic fibrosis.
Let's call the gene "C." Capital C means no cystic fibrosis; lower c means cystic fibrosis, since it is a recessive gene. CC is a person who does not have cystic fibrosis and also is not a carrier. Cc indicated a carrier. cc shows a person with cystic fibrosis. In order for a child to have cystic fibrosis, its parents must be: 1. cc and cc (both have cystic fibrosis, so every child will as well.) 2. Cc and Cc (both carriers; 25% chance of having a child with cystic fibrosis) 3. Cc and cc (one parent is a carrier and one has cystic fibrosis; there is a 50% chance that the children will have cystic fibrosis.)
The mother and father both have one mutated cystic fibrosis gene. If the child receives genes from the mother and the father that are both mutated, then the child will develop cystic fibrosis. If the child receives only one chromosome containing the CFTR(cystic fibrosis transport regulator: the gene that is mutated in cystic fibrosis), then the child will not develop CF. He will still have the CF gene, but it is a recessive trait, so you need two of these chromosomes that contain the mutated gene to develop the symptoms of CF and be affected by it. Use a punnet square if you still don't understand :)
Cystic fibrosis is a inherited disease where ususally by the time of 30-35 the person who has it does die.
Assuming that each parent is a carrier for cystic fibrosis (has the genotype Ff), the probability that their second child will develop cystic fibrosis is one fourth. The probability doesn't change with the number of children they have. For each pregnancy, the chance that the child will have cystic fibrosis (have the genotype ff) is exactly the same.
Cystic fibrosis is genetic and is not contagious A person gets it when he/she inherits two mutated genes off each parent. A healthy couple can have a child with Cystic fibrosis because the parents would be carriers of the disease (even though they are unaffected by it themselves). 25% of children are at risk of the disease as it can be passed down from previous generations.
Both cystic fibrosis and sickle cell anemia are single mutation diseases - one mutation in a single gene is enough to cause the disease. However, for cystic fibrosis both alleles of the gene must be mutated for the disease to develop. For sickle cell anemia, only one allele can carry the mutation and some signs of the disorder will be present. Having two alleles with the mutation causes much more significant disease.
cystic fibrosis is hereditary but your children will only have a chance at having it if there are at least four children its a one in four kinda thing but they will need to get tested for being a carrier of the cf gene
this is so false, no he did not