0
The question itself is controversial, as we're not sure if the observer has anything to do with the wave collapse.
However, once the ability to observe (or interact) with a given particle is enabled, the wave-function or probability wave of that particle peaks, or collapses into a finite quantity.
As said, we're not sure if a conscious observer has anything to do with it, or if it has to do with physical interactions in and of themselves.
Another opinion:
The observer has nothing to do with the collapse of the wave function. It is the measurement acting on the the wave function that does the collapsing. The part about which we are uncertain (we, as in physicists) is whether nature performs the measurement before we do and we get the result, or if nature leaves the wave function as a superposition until we measure it. This is the fundamental question of Schrodinger's cat in a box paradox.
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
How will you calculate potential if the wave function is given?
Square the wave function.
What is normalising a wave function?
A wave function is normalized by determining normalization constants such that both the value and first derivatives of each segment of the wave function match at their intersections. If instead you meant renormalization, that is a different problem having to do with elimination of infinities in certain wave functions.
Why doesn't the Doppler shift appear when an observer moves toward the source?
Doppler's effect does not happen when the observer is moving towards the source because unlike the source when observer moves forward the waves are not compressed and they pass the observer without being compressed and since the doppler effect is due to the Change in wavelength of the wave, it fails to occur.
What is the derivation of the wave function?
A simple wave function can be expressed as a trigonometric function of either sine or cosine. lamba = A sine(a+bt) or lamba = A cosine(a+bt) where lamba = the y value of the wave A= magnitude of the wave a= phase angle b= frequency. the derivative of sine is cosine and the derivative of cosine is -sine so the derivative of a sine wave function would be y'=Ab cosine(a+bt) """"""""""""""""""" cosine wave function would be y' =-Ab sine(a+bt)
What is well behaved wave function?
List of the characteristics a well-behaved wave function are ..The function must be single-valued; i.e. at any point in space, the function must have only one numerical value.The function must be finite and continuous at all points in space. The first and second derivatives of the function must be finite and continuous.The function must have a finite integral over all space.
Frequency of a wave?
The frequency of a wave is the amount of cycles that pass the observer in any time.
what is wave function?
The official definition for the word wave function is "a function that satisfies a wave equation and describes the properties of a wave."
Would there be a Doppler effect if the source of a wave is stationary and the observer is the one in motion?
Yes. The observer frequency fo= f( v + vo)/(v -vs) where f is the signal frequency, v is the speed of wave and vo is the speed of the observer towards the signal and vs is the speed of the signal toward the observer.
What is A change in the observed wavelength or frequency of a wave that occurs when the source of the wave or the observer is moving?
Doppler Effect :)
How will you calculate potential if the wave function is given?
Square the wave function.
Does the Doppler effect happen with light?
Yes, the Doppler effect can be applied to light. Any wave function can be subject to the Doppler effect if there is relative motion between the source and an observer. That's how we know that the Universe is expanding.
What is the observed change in the frequency of a wave when either the source or observer is moving?
Doppler shift
What are the Differentiate the sine wave and cosine wave?
The differential of the sine function is the cosine function while the differential of the cosine function is the negative of the sine function.
What kind of wave is an echo?
An echo of a wave is exactly the same type of wave as the original wave. An echo is simply the original wave returning to the observer, so if you made a sound (a longitudinal wave of vibrating air molecules), the echo is also sound waves.
Can god be explained by quantum physics?
Quantum physics does not provide a definitive explanation for the existence of a god or deity. The field of quantum physics focuses on the behavior of particles at the subatomic level, while the concept of a god typically involves questions of faith, spirituality, and philosophy that fall outside the realm of scientific inquiry.
What is normalising a wave function?
A wave function is normalized by determining normalization constants such that both the value and first derivatives of each segment of the wave function match at their intersections. If instead you meant renormalization, that is a different problem having to do with elimination of infinities in certain wave functions.
Why doesn't the Doppler shift appear when an observer moves toward the source?
Doppler's effect does not happen when the observer is moving towards the source because unlike the source when observer moves forward the waves are not compressed and they pass the observer without being compressed and since the doppler effect is due to the Change in wavelength of the wave, it fails to occur.
