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Ethanoic acid is fully soluble in water, but it will react with sodium hydroxide.
Yes, ethanoic acid (acetic acid) is soluble in sodium hydroxide. When acetic acid reacts with sodium hydroxide, it forms sodium acetate and water. Sodium acetate is a water-soluble salt, hence leading to the solubility of acetic acid in sodium hydroxide.
Hydrogen gas is given off when ethanoic acid (acetic acid) reacts with magnesium. This is a result of the displacement reaction between the acid and the metal.
Magnesium acetate in solution, crabon dioxide released as a gas.
Magnesium hydroxide is not an acid nor does it contain one. Like other hydroxides it is a base.
Hydrochloric acid and magnesium hydroxide react to form magnesium chloride and water.
The chemical equation for the reaction between ethanoic acid (acetic acid) and sodium hydroxide is: CH3COOH + NaOH → CH3COONa + H2O This reaction is a neutralization reaction that forms sodium acetate and water.
The salt formed when magnesium hydroxide is neutralized by hydrochloric acid is magnesium chloride (MgCl2). This is because the H+ ions from the hydrochloric acid replace the OH- ions from magnesium hydroxide, leading to the formation of magnesium chloride and water.
The reaction between ethanoic acid (acetic acid) and sodium hydroxide is a double replacement one. Normally a reaction between an acid (acetic acid in this case) and a base (like NaOH) involves neutralization, which in turn produces water.
The reaction between ethanoic acid and ammonium hydroxide forms ammonium acetate, water, and ammonia gas. The balanced chemical equation for this reaction is: CH3COOH + NH4OH -> NH4CH3COO + H2O + NH3.
Magnesium nitrate (salt) and water are produced.
The products formed are magnesium chloride and water.