1,3,1,3
To determine the theoretical yield of chromium produced, you first need to balance the chemical equation for the reaction between Cr2O3 and aluminum. Next, calculate the molar mass of Cr2O3 to find the moles used in the reaction. Use the stoichiometry of the balanced equation to find the moles of chromium that can be produced, and then convert that to grams.
In the balanced chemical equation 4 Cr(s) + 3 O2(g) → 2 Cr2O3(g), there are a total of 6 chromium atoms (2 from Cr and 4 from Cr2O3) and 6 oxygen atoms (6 from O2 and 3 from Cr2O3) on the right side of the equation.
Cr2O3 is an oxide.
Cr2O3 is an ionic compound. It is composed of chromium (Cr) and oxygen (O) ions that are held together by ionic bonds.
(NH4)2 Cr2 O7 --------> N2 + 4H2O + Cr2 O3
Cr2O3 is known as Chromium(III) oxide. Please see the "related links" below for more information about this compound.
The percent composition of Cr2O3 is approximately 68% Chromium (Cr) and 32% Oxygen (O).
"Chromium(III) oxide", or "dichromium trioxide".
Cr2O3 is the chemical formula for chromium (III) oxide
Your unbalanced equation is _Al + _Cr2O3 ----> _Cr + _Al2O3. Multiply aluminum (Al) and chromium (Cr) ratio by 2, so each side has the same amount of each element. As a result, the equation 2Al + Cr2O3 -----> 2Cr + Al2O3 is balanced. This is a single replacement reaction.
The compound Cr2O3 is chromium(III) oxide. It is a naturally inorganic occurring compound and it is used primarily as green pigment.
The chemical reaction between Cr2O3 and SO3 forms chromium sulfate (Cr2(SO4)3).