It depends on what the side lengths are for the first triangle
Technically, you can't. The Koch snowflake is self-similar. So the perimeter is infinity.
you find the area of a koch snowflake using z=(n-1)x/3
A variety of such shapes can be constructed; a well-known example is the Koch snowflake. http://en.wikipedia.org/wiki/Koch_snowflake
1904
Yes.
It is a fractal: each enlargement of the snowflake is an identical image.
Yes - as you "zoom in" on the sides of the snowflake, the same pattern occurs infinitely.
an infinite number.
A Koch curve has INFINITE length.
The von Koch snowflake is infact a fractal that looks like a snowflake. It is made by starting with an equilateral triangle. The next step is to remove the middle third of each line and add two edges of the same length as the removed segment across the gap. Now all 12 of the edges are equal length and the whole shape should now look like the star of David. Now remove the middle of third of each of the twelve edges and add another "spike" to each. Keep repeating this over and over ad infinitum and you have the Koch snowflake.
Either the koch snowflake or the Sierpinski triangle
yes! the best example would be the Koch snowflake.