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A = arcsin 12
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If θ is an acute angle and sin θ equals 12 then cos θ equals?
The value of sine and cosine varies between -1 and 1, it never can be 12. If you mean .12, then we have: sin x = .12 x = sin-1 .12 x = 6.89 degrees So that, cos x = cos 6.89 = .99
Solve the right triangle with A equals 52 degrees 15' and a equals 6.7808?
Angle A = 52° 15' = 52 25° therefore angle B = 90 - 52.25 = 37.75°. Using the Sine Rule : a/sin A = b/sin B. 6.7808/sin 52.25 = b/sin 37.75 : b = 6.7808 sin 37.75 ÷ sin 52.25 = 5.2503 Either using the Sine Rule or Pythagoras gives the length of the hypotenuse as 8.5758
How sin90degree equals 1?
Sin = Opposite/ Hypotenuse. If the angle is 90o then the Opposite IS the Hypotenuse so the ratio is 1.
How sin90 equals 1?
Because sin = opp/hyp and the opposite side to a 90 degree angle is the hypotenuse.
True or false in triangle ABC with the right agnel at C if B equals 13.5 and C equals 28.9 then angle B equals 27.8?
True : Sin B = 13.5/28.9 = 0.46713 : Therefore Angle B = 27.8 (1dp)
Tan equals 0.3421 sin equals 3237 Which quadrant does it terminate?
Assuming sin equals 0.3237, the angle is in quadrant I.
If θ is an acute angle and sin θ equals 12 then cos θ equals?
The value of sine and cosine varies between -1 and 1, it never can be 12. If you mean .12, then we have: sin x = .12 x = sin-1 .12 x = 6.89 degrees So that, cos x = cos 6.89 = .99
What is the sin of angle A 5 13 12?
The dimensions given fits that of a right angle triangle and sin^-1(12/13) = 67.38 degrees
If θ is an acute angle and sin θ equals 2 then cos θ?
it equals 4
In triangle abc given that angle a equals 57 angle b equals 73 and ab equals 24cm find the length of ac?
The sum of the angles inside a triangle is equal to 180°. We are told that angle a is 57°, and that angle b is 73°. This tells us that angle c is is (180 - 57 - 73)°, or 50°. We are also given the length of side ab, 25cm. With that, we can use the sine rule to calculate the length of side ac: sin(b) / |ac| = sin(c) / |ab| ∴ sin(73°) / |ac| = sin(50°) / 24cm ∴ |ac| = 24cm · sin(73°) / sin(50°) ∴ |ac| ≈ 29.96cm
Sine of 10 degrees x 12 equals?
Sin(10)*12 = 12*sin(10) = 12*0.1736 = 2.0838, approx.
Solve the right triangle with A equals 52 degrees 15' and a equals 6.7808?
Angle A = 52° 15' = 52 25° therefore angle B = 90 - 52.25 = 37.75°. Using the Sine Rule : a/sin A = b/sin B. 6.7808/sin 52.25 = b/sin 37.75 : b = 6.7808 sin 37.75 ÷ sin 52.25 = 5.2503 Either using the Sine Rule or Pythagoras gives the length of the hypotenuse as 8.5758
How sin90degree equals 1?
Sin = Opposite/ Hypotenuse. If the angle is 90o then the Opposite IS the Hypotenuse so the ratio is 1.
How sin90 equals 1?
Because sin = opp/hyp and the opposite side to a 90 degree angle is the hypotenuse.
True or false in triangle ABC with the right agnel at C if B equals 13.5 and C equals 28.9 then angle B equals 27.8?
True : Sin B = 13.5/28.9 = 0.46713 : Therefore Angle B = 27.8 (1dp)
The refractive index of water is 1.33 a ray is incident from water on air at an angle of incidence equal to 30 degree what is the angle of refraction in air?
The angle of refraction can be calculated using Snell's Law: n1sin(theta1) = n2sin(theta2), where n1 and n2 are the refractive indices of the media, and theta1 and theta2 are the angles of incidence and refraction, respectively. Given n1 = 1.33, n2 = 1 (since in air), and theta1 = 30 degrees, we can solve for theta2 to find it is approximately 22.62 degrees.
If the area of triangle ABC is 27cm2 BC is 12cm and angle BCA is 98 degrees what is length AC?
Area = 1/2*a*b*sin(C) where a = BC, b = AC and angle C = angle BCA 27 = 0.5*12*AC*sin(98) So AC = 27/[0.5*12*sin(98)] = 4.54 approx.
