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To find use the following equation

object size = distance x (smallest angle/57.3°)

Since Arecibo is on Earth, to find the distance take the distance between the sun and Earth (in AU) and subtract the distance between the sun and Venus (in AU). Then multiply the AU by 1.5 x 108 (or the number of kilometers in 1 AU)

1 AU - 0.72 AU = 0.28 AU

0.28 AU x 1.5 x 108 = 4.2 x 107 km

For 1'

object size = 4.2 x 107 x (1/60°/57.3°)

object size = 12216.4 km

For 1"

object size = 4.2 x 107 x (1/3600°/57.3°)

object size = 203.6 km

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Q: What is the size of the smallest feature that could be distinguished on the surface of Venus by the Arecibo radio telescope at an angular resolution of 1?
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