Slope-intercept form: y=mx+b
what is the yintercept for y=2/3x-8
The slope is 1 and the y intercept is 2
7x is still the slope, no matter what x equals.
The slope is negative 2/3.
Assuming y = -2x + 1; -2 is the slope.
The slope of -x plus 6y is equals to 12 is said to be (2 + 1/6x).
2x + y = 20 y = -2x + 20 Slope = -2 m=-2
y = 0.25x + 2 The slope of the line is 0.25
In the form y = mx + c, m is the slope, thus: x + y = 2 → y = -x + 2 → slope = -1
The slope of the perpendicular is -(1/2) .
The slope is the coefficient of x in the standard form and so it is 2.
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
rewrite the equation in terms of y y = 1-2x the slope is -2
the slope is 2, the number in front of the 'x' term
If: y = -2/3x+2 then the slope is -2/3 and the y intercept is 2
5x+3y = -2 3y = -5x-2 y = -5/3x-2/3 Slope: -5/3
The slope is 2 over 3. In other words, you go up 2 and go 3 to the right.
[ y = 2x + 5 ] has a slope of 2. [ y = 2 ] is a horizontal line ... its slope is zero. Their slopes are different, so they're not parallel.
y=-2x+6 This is in slope-intercept form: y=mx+b slope (m) = -2
the slope is - 2 and the y intercept is 4
y=3x+(3/2), so the slope is 3 or (3/1).
5 and the y intercept is 2
y = -3x + 2 The gradient or slope is -3
Do you mean: 1/3x+2 = y if so then the slope is 1/3 and the y intercept is 2
The slope would be -2 (moving 2 units down and one across). When you have a linear equation, the slope is always the variable's coefficient.