Using: y2-y1 over x2-x1 the slope is -1/14
Using: y = mx+c the equation is y = -1/14x-19/28 which can be expressed in the form of 2x+28y+19 = 0
y = 2.25x -6
2y+x+5 = 0
The general form is 11x - 10y + 19 = 0
If you mean points of (2, -3) and (4, 2) then the slope is 5/2 and the straight line equation is 2y = 5x-16
The equation is x = 2
y = 2.25x -6
2y+x+5 = 0
Y=4x+3
The general form is 11x - 10y + 19 = 0
If you mean points of (2, -3) and (4, 2) then the slope is 5/2 and the straight line equation is 2y = 5x-16
The equation is x = 2
If the line passing through these points is a straight line then it has a positive gradient.
Points: 0 2 and 6 0 Equation: y = -1/3x+2
The straight line equation works out as: y = 1/3x+7 So: k = 8
y = -1/14x-19/28 which can be expressed in the form of 2x+28y+19 = 0
x = 2
The formula for a line is: Y = mX + b