Top Answer

x-2y+8 = 0

-2y = -x-8

y = 1/2x+4 in slope intercept form and the slope of the line parallel to it is 1/2

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0the slope of the line is -4

The slope of the line of 2x plus 2y equals 7 is (7/2x - 1).

Slope of given line = -3 Therefore, slope of perpendicular = 1/3

The slope is negative 2/3.

what is the slope of the line that has the equation 4x+2y=12?

The slope of the perpendicular is -(1/2) .

For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )

It equals the slope of the line y = -x. That's a pretty darn strong hint right there is what that is.

y = 0.25x + 2 The slope of the line is 0.25

That is slope-intercept form of a line.

The slope is -6 and the y intercept is 12

Yes, that is the slope intercept form of the equation for a straight line.

The slope is 1 and the y intercept is 5

The slope of a line perpindicular to y=-2x+5 is 1/2 because a perpindicular slope is the negative reciprocal of the slope.

The graph of the equation is a straight line. 'm' is its slope. 'b' is its y-intercept

the slope is 2, the number in front of the 'x' term

The slope of the line that represents the graph of that equation is 15.

After solving for y you will get y=1/5 x+1. The slope of this line is 1/5.

the slope will be positive 1.5x the whole equation is y=4.5+1.5x

If: 3x+y = -4 Then: y = -3x-4 and the slope of the line is -3

line in data is y=-2X+6 The perpendicular line will have a slope of = +1/2 Note : m X m' = -1 , m= slope of line 1 ; m'= slope of perpendicular line to line 1

y = mx + c is the equation of a straight oblique line where m = gradient The gradient is a measue of the steepness of a line (or a measure of the slope of the line)

The slope of the perpendicular to a line has a slope which is the negative reciprocal of the original line's slope.The negative reciprocal of x is -1/xSo in this case, where the slope is -2 the perpendicular line has the slope -1/(-2) or simply 1/2

Minus one half, (-1/2).

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