3x + 4y = 12 can be written as 4y = -3x + 12 , which can be simplified to, y = -3/4x + 3
The slope of this line is the coefficient of x, namely, -3/4.
When two straight lines are perpendicular then the product of their slopes/gradients is -1.
Therefore , any line perpendicular to y = -3/4x + 3 has the slope 4/3.
Now select any point on the original line where you wish to create the perpendicular line. Let the coordinates of this point be (a, b).
The general slope/intercept form of equation for a straight line is y = mx + c. Substituting the values of the ordered pair gives : b = 4/3a + c
The two lines intersect at (a, b) and at that point, -3/4x + 3 = 4/3x + c
Then, -3/4a + 3 = 4/3a + c : c = -25/12a + 3
The equation of the perpendicular line is thus : y = 4/3x - 25/12a + 3
2/3.
5
the slope will be positive 1.5x the whole equation is y=4.5+1.5x
x = -3 represents a vertical line whose slope is undefined.
1, it will have the same slope but the y intercept will be different.
y = 0That's the equation of the x-axis.Its slope is zero.
The slope would be 3/4
7
17/12
2/3.
5
The slope is 5. Parallel lines always have the same slope.
1.67 or 1.667
the slope will be positive 1.5x the whole equation is y=4.5+1.5x
x = -3 represents a vertical line whose slope is undefined.
1, it will have the same slope but the y intercept will be different.
-5