Calcium carbonate.
When sodium carbonate solution is mixed with calcium chloride solution, a white precipitate of calcium carbonate forms. This is a double displacement reaction where the sodium and calcium ions swap partners to form insoluble calcium carbonate.
You have answered the question for yourself. Calcium + Chlorine = Calcium chloride. The BALANCED reaction equation is Ca(s) + Cl2(g) = CaCl2(s)
It all depends on the type of Calcium Chloride you used. Was it anhydrous or dihydrate or else?
you put the thing into the other thing that equals z
nothing, a new product can not be formed because their anions are common.
calcium carbonate + hydrochloric acid -> Carbon dioxide + Water+ Calcium Chloride In general, when a carbonate is added to an acid, the equation will be carbonate + acid -> salt + water + carbon dioxide
Calcium plus carbon plus oxygen plus oxygen plus oxygen equals calcium carbonate (CaCO3), which is a chemical compound that forms when calcium reacts with carbon and oxygen.
The carbonate compensation depth (CCD) is the depth in the ocean at which the rate of calcium carbonate production equals the rate of dissolution. Below this depth, calcium carbonate dissolves due to increased pressure and decreasing pH, preventing accumulation. The CCD varies with ocean chemistry, temperature, and biological activity.
No, one atom of the element Calcium (Ca) reacts with a molecule of Chlorine Gas which has two atoms of chlorine (CL2) to form on molecule of Calcium chloride (CaCl2) :-Ca + CL2 = CaCL
It would be unethical to use this service to answer exam or graded questions. CaCl2 + 2NaOH --> 2NaCl + Ca(OH)2 Calcium Chloride + Sodium Hydroxide --> Sodium Chloride + Calcium Hydroxide Why: Ca ion has 2+ charge Cl ion has 1- charge Na ion has 1+ charge OH polyatomic ion has 1- charge
The product of Cu + Cl2 reacting to form CuCl2 is copper(II) chloride. In this reaction, the copper (Cu) reacts with chlorine (Cl2) to form copper(II) chloride (CuCl2) as the product.
calcium + oxygen --> calcium oxide Ca + O --> CaO