6x2-24=0
6(x2-4)=0
x= {-2,2}
x = +/- 2
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
6x2 + 9x = 0 3x(2x + 3) = 0 3x = 0 or 2x + 3 = 0 x = 0 or x = -3/2
I think the answer is either 7776 or 0
To graph the solution set for b is not equal to 0 on a number line, you would first place a filled-in circle at 0 to indicate that 0 is not included in the solution set. Then, draw a ray extending to the left and another extending to the right, indicating that the set includes all numbers except 0. No other markings or filled-in circles are needed since all numbers, positive or negative, except 0, are part of the solution set.
6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
6x2-x = 1 6x2-x-1 = 0 (2x-1)(3x+1) = 0 x = 1/2 or x = -1/3
6x2 - x - 15 = 0 since (6)(-15) = (-10)(9) and -10 + 9 = -1, then factor as: [(6x + 9)/3][6x - 10)/2] = 0 (2x + 3)(3x - 5) = 0 let each factor be zero: 2x + 3 = 0 or 3x - 5 = 0 solve for x: The solutions are: x = -3/2 and x = 5/3
6x2 + 9x = 0 3x(2x + 3) = 0 3x = 0 or 2x + 3 = 0 x = 0 or x = -3/2
I think the answer is either 7776 or 0
x-2y=0 x=2y The solution set is the set of all (x,y) such that x=2y
x = -1/3 or 11/2 3 = 6x2 - 7x ⇒ 6x2 - 7x - 3 = 0 ⇒ (3x + 1)(2x - 3) = 0 ⇒ (3x + 1) = 0 → x = -1/3 or (2x - 3) = 0 → x = 11/2
6x2+13x-5 = 0 (2x+5)(3x-1) = 0 x = -5/2 or x = 1/3
a = [ 0, 4 ]
do it yourself
15x2-56 = 88+6x2 15x2-6x2-56-88 = 0 9x2-144 = 0 Divide all terms by 9:- x2-16 = 0 (x-4)(x+4) = 0 x = 4 or x = -4
To graph the solution set for b is not equal to 0 on a number line, you would first place a filled-in circle at 0 to indicate that 0 is not included in the solution set. Then, draw a ray extending to the left and another extending to the right, indicating that the set includes all numbers except 0. No other markings or filled-in circles are needed since all numbers, positive or negative, except 0, are part of the solution set.