What is the specific heat capacity 0f 50 grames solid at 80 degrees Celsius put in water of 100 grames at 25 degrees Celsius if final temperature of both was 30 degrees Celsius?

Answer 1

Two q's to 0. q = mass * specific heat * change in temp.. Q falls out of equation

(50 g)(X specific heat)(30 C - 80 C) + (100 g H2O)(4.180 J/gC)(30 C - 25 C) = 0

(- 2500X) + (2090) = 0

- 2500X = - 2090

X = 0.836 J/gC

=============the specific heat of the solid