a few hundred FPS to multiple thousands of FPS depending on the exact weapon.
Gun powder.
The momentum of the bullet is equal and opposite to the momentum of the gun. Momentum = mv. Bullet =mbvb Gun = mgvg These are equal, with their speeds in opposite directions. mbvb = mgvg vg = vb x mb/mg = vb x (60/5000) = 0.012 vb The recoil speed of the gun is 0.012 the muzzle speed of the bullet. The question says vb is "500ms", which is unclear. If it is meant to indicate "500 meters per second", then the recoil speed is (500 x .012) = 6 m/s.
The mass of a bullet is nowhere near the mass of a gun. A bullet weighs at most a few hundred grains. Most guns weigh at least a couple of pounds, some weigh several pounds (talking about handguns and rifles).
Newton said "For every action, there is an equal and opposite reaction." The action is pushing the bullet in one direction. Reaction is the gun being pushed in the other. The energy is speed times mass. The gun masses much more than the bullet, and so will move proportionately slower than the bullet. Which is a very good thing- or the recoil of the gun would kill the shooter.
yes if your arm is moving at the same speed as the bullet as it leaves the gun
because the recoil is when the bullet forces the gun back and so the bullet creates the recoil and so it can't make it go just as fast
Using the principle of conservation of momentum, we can calculate that the gun will recoil at 0.08 m/s in the opposite direction of the bullet. The total momentum of the gun and bullet before firing is equal to the total momentum after firing.
The question is too vague because it depends on several factors such as, gun barrel length, bullet design, bullet weight.
Yes, a bullet can be shot with no gun. A bullet does not need a lot of speed to kill someone. Say someone threw a bullet to the ground, it might bounce back up and hit you, thus causing you to die or be injured
By conservation of momentum, the momentum of the gun and bullet system before firing must equal the total momentum after firing. Therefore, the velocity at which the gun recoils can be calculated by using the equation: (mass of bullet * velocity of bullet)/mass of gun = velocity of gun. Substituting the values given: (0.06 kg * 500 m/s) / 5 kg = 6 m/s.
The momentum of a bullet fired from a gun is the product of its mass and velocity. It is a vector quantity that represents the motion of the bullet in a specific direction and is conserved in the absence of external forces.
The gun and the bullet are already traveling at a high speed. Firing the gun results in the bullet leaving the gun. Its relative velocity to someone standing still would be twice the speed. But its relative velocity to the gun would simply be the normal speed of the bullet. A similar question is the one if your traveling in a car at the speed of light what would happen when you turn on the headlights? No one is really sure. in short, the bullet would go twice the regular speed in a vacuum. I agree with the first bit and have ed a similar question on here. I find the vacuum bit of the above a bit irrelevant. A bullet fired in a vacuum would emerge at the normal speed (around 2,000+mph for a rifle round) but would carry on forever as there would be no air resistance.