0
What is the speed of an object when it is moving so that its kinetic energy is 93.3 J and the magnitude of its momentum is 37.9 kg meters per sec?
Wiki User
∙ 14y ago
Momentum = (m V) = 37.9
KE = (1/2 m V2) = 93.3
1/2 m V2 = (1/2 V) (m V) = 93.3
(1/2 V) (37.9) = 93.3
1/2 V = 93.3/37.9
V = 2 x 93.3 / 37.9 = 4.9235 meters per second (rounded)
Bonus ! ... now we also know that the object's mass is [ 37.9 / 4.9235 ] = 7.697 kg (rounded)
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
How will the momentum of a body changes if its Kinetic energy is doubled?
Let's see. Mass constant. 625000 Joules = 1/2(500 kg)V2 1250000 Joules = 500V2 2500 = V2 50 meters/second = velocity ==================================== The velocity doubles if KE doubles.
Is touching a kinetic energy?
Kinetic energy is the energy of motion. Your touching finger has mass and is moving some meters per second, so that motion is kenetic energy.
When a bulltet is fired from a rifle it is the bullet which causes damage but nit recoiling gun answer you according to momentum or third law of motion?
I believe that you are asking if the bullet is what causes so much damage to something it strikes, then why doesn't the shooter suffer an equivalent amount of damage? The answer does have a lot to do with momentum. I think that there may be some confusion between the conservation of momentum, which is the essence of Newton's Third Law, and the definition of kinetic energy.The magnitude of the momentum of the bullet just as it leaves the barrel of a gun is equal to, but in the opposite direction of, the magnitude of the momentum of the gun plus any momentum imparted to the shooter's body.I apologize if you already know much of my answer, but I will show the equations for momentum and kinetic energy. Momentum is a vector because it has both direction and magnitude, and the equation for momentum is p = m•v, where p is momentum, m is the object's mass in kg, and v is the object's velocity in meters/sec. (The vector quantities are in bold. I'm using the units prescribed in the kms system.)The reason the bullet causes damage to whatever it strikes is due to the bullet's kinetic energy, which is defined by the equation Ek=1/2mv2, where m is the mass of the bullet in kg and v is the bullet's speed in meters/sec. The fact that the kinetic energy is proportional to the square of the velocity is of paramount importance. Just like momentum, energy is also conserved. Energy (or the combination of energy and mass in the cases of nuclear fission and nuclear fission) is never lost; it can only change forms. All the energy released from every bullet, bomb, and shell used in World War II, or any other war, is still present somewhere in the universe, although almost all of it is still present on the Earth in some form. Thus, the kinetic energy of a bullet fired from a gun is initially exactly equal to the kinetic energy imparted to the backward-moving gun, the gun's report, the flash of light from the muzzle, the heating of the gun's receiver, chamber, and barrel, the heating of the bullet and of whatever it hit, the frictional heating of the air through which the bullet passed, and the energy expended in damaging what the bullet struck.The reason the shooter of the gun is not severely damaged (although anyone who has ever fired a very powerful rifle such as a 375 H&H or a 460 Wetherby Magnum might disagree) is because the energy of the bullet is proportional to the square of the velocity. Because the mass of the gun is so much greater than the mass of the bullet, the rearward velocity of the gun is very much less than the velocity of the bullet such that the gun cannot cause significant damage to the shooter.
If you have a 2kg pendulum bob that is 6 meters above the ground at its high point and 1 meter at its low point how can you figure the kinetic energy?
Calculate the potential energy at its highest point. Don't use the 6 meters above the ground - use the 5 meter difference from the lowest point. This part of the potential energy gets converted into kinetic energy, when the pendulum is at its lowest point. Just assume that all the potential energy (for the 5 meters difference) get converted into kinetic energy.Calculate the potential energy at its highest point. Don't use the 6 meters above the ground - use the 5 meter difference from the lowest point. This part of the potential energy gets converted into kinetic energy, when the pendulum is at its lowest point. Just assume that all the potential energy (for the 5 meters difference) get converted into kinetic energy.Calculate the potential energy at its highest point. Don't use the 6 meters above the ground - use the 5 meter difference from the lowest point. This part of the potential energy gets converted into kinetic energy, when the pendulum is at its lowest point. Just assume that all the potential energy (for the 5 meters difference) get converted into kinetic energy.Calculate the potential energy at its highest point. Don't use the 6 meters above the ground - use the 5 meter difference from the lowest point. This part of the potential energy gets converted into kinetic energy, when the pendulum is at its lowest point. Just assume that all the potential energy (for the 5 meters difference) get converted into kinetic energy.
If an object weighing 90 kilograms and moving with a velocity of 20 meters per second has a kinetic energy of 4500 Joules. what is its kinetic energy when the velocity is 32 meters per second?
KE=(1/2)mv246080 Joules
How will the momentum of a body changes if its Kinetic energy is doubled?
Let's see. Mass constant. 625000 Joules = 1/2(500 kg)V2 1250000 Joules = 500V2 2500 = V2 50 meters/second = velocity ==================================== The velocity doubles if KE doubles.
Why does heavier object have a greater momentum if light and heavy object have the same kinetic energy?
Well, the equation for momentum is mass x velocity. So, p (momentum)= m x v. The equation for kinetic energy is m x v(squared)/2. Let's say that there are two objects. One is 50 kg, and the other is 30 kg. These objects can both have the same kinetic energy, even though one of them has a larger mass. The determining factor in them both having the same kinetic energy, even though one of them has a larger mass is because of different velocities. The 50 kg object has a velocity of 7 meters/second, and the 30 kg object has a velocity of 9.036961141 meters/second. If you do the math, they both have the same kinetic energy (about the same). 50 kg x 7 m/s = 350 kg x m/s. 30 kg x 9.036961141 = 271.1088342. There is an inverse relation between the momentum of an object and its mass. The mass is the factor that influences momentum more than the velocity; that is why an object with a greater mass will have a greater momentum than the one with a lesser mass, only if they both have the same kinetic energy.
A 5kg object is being lifted to a height of 8 meters and is dropped what is the kinetic energy of the object at 2 m?
After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.After falling 6 meters, potential energy corresponding to those 6 meters will be converted to kinetic energy. The potential energy (for the 6 meters) is mgh = (5 kg)(9.82 m/s2)(6 m) = 294.6 J, so that is also the kinetic energy, since potential energy has been converted to kinetic energy.
What is the momentum of a 25kg sheep traveling east at 10ms?
The sheep's momentum vector has a magnitude of 250 kilogram-meters per second,and a direction of east.
Which has more momentum a 1000 kg car moving 1 meters per second or a 70 kg person sprinting at 8 meters per second?
Kinetic Energy is E = 1/2 * m * V^2Therefore the car has an energy of 500 joules.There person has an energy of 32 joules.I'm not completely sure about how that equates to momentum but that car certainly has much more energy due to its greater mass.
If a scooter has a mass of 20 kg and a velocity of 18 m's north what is the magnitude of its momentum?
Momentum = m V = 20 x 18 = 360 kgm-meters
What is the mathmetical formula for kinetic energy?
Kinetic Energy = 1/2(mass in kilograms)(meters per second)2
What is the energy of a system by virtue of its motion?
That's called kinetic energy. The formula is: Kinetic energy = (1/2) x mass x velocity2. If mass is in kilograms, and velocity (or speed, really) in meters per second, the energy will be in Joules.
Is touching a kinetic energy?
Kinetic energy is the energy of motion. Your touching finger has mass and is moving some meters per second, so that motion is kenetic energy.
What are the factors in kinetic energy?
Kinetic energy = 1/2 x mass x velocity2. Mass in Kg, velocity in meters/sec, energy in Joules
What is the magnitude of the velocity of a 25-kilogram mass that is moving with a momentum of 100 kilogram-meters per second?
-75
What will be the kinetic energy and velocity of object of mass 62kg?
Its kinetic energy (in joules) will be (31) times (its velocity in meters per second)2 .
