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Impact velocity depends on the mass of the object and the height it falls from. It is the speed at which the acceleration due to gravity is maximized.
There is no definite speed for free falling. If an object is released somewhere above the earth, the speed is changing every single moment. It is never the same speed it was before at any time; only until an object releases terminal velocity where it is moving at a constant speed. This is different for every object. The acceleration due to the gravity of the earth is 32 feet/second^2. This means that for every second that passes, an object is moving 32 feet/second faster than it was the second before.
19.6 meters per second
In order to answer this, you have to make two assumptions: #1). We're talking about a falling object on or near the Earth. #2). We're ignoring the effects of air resistance. If both of those are true, then the falling object picks up speed as it falls. At any moment, its speed is 9.8 meters per second (32.2 feet per second) faster than it was one second earlier. That number is called the "acceleration of gravity" on Earth. Notice that the mass or weight of the object doesn't matter. You asked for the velocity, which means speed and direction. I've explained the speed, and the direction is always down.
1.the speed 2.air 3.force
The mass of a falling object will affect the speed at which it falls. Additionally, the shape or geometryof that object will also have an effect. The shape of a falling object will have a dramatic effect on the amount of dragthat the object will experience. Consider that a flat piece of cardboard will fall more slowly than a glass ball of the same mass, and it will be more easy to visualize how drag is a function of shape.=======================================Beulah the Buzzer gagged on the first sentence of the response above, andSignor Galileo rotated 2pi in his crypt.The mass of a falling object will NOT affect the speed at which it falls.The remainder of the response above is correct and well stated, provided onlythat the objects are falling through air. If not, then neither their shape nor theirgeometry affects their rate of fall either.
Impact velocity depends on the mass of the object and the height it falls from. It is the speed at which the acceleration due to gravity is maximized.
An object affected by the gravity of the Earth is falling at 9.8 meters per second per second, also written as 9.8 m/s^2.
There is no definite speed for free falling. If an object is released somewhere above the earth, the speed is changing every single moment. It is never the same speed it was before at any time; only until an object releases terminal velocity where it is moving at a constant speed. This is different for every object. The acceleration due to the gravity of the earth is 32 feet/second^2. This means that for every second that passes, an object is moving 32 feet/second faster than it was the second before.
19.6 meters per second
In order to answer this, you have to make two assumptions: #1). We're talking about a falling object on or near the Earth. #2). We're ignoring the effects of air resistance. If both of those are true, then the falling object picks up speed as it falls. At any moment, its speed is 9.8 meters per second (32.2 feet per second) faster than it was one second earlier. That number is called the "acceleration of gravity" on Earth. Notice that the mass or weight of the object doesn't matter. You asked for the velocity, which means speed and direction. I've explained the speed, and the direction is always down.
1.the speed 2.air 3.force
2.
19.614 meters/second is.
Terminal velocity, the highest speed of an object is, F_w=\frac{1}{2}C_D \rho A_F v^2 .
Falling object acceleration is due to gravity, and is therefore a constant. However, because there is a magnitude to this acceleration, the falling object will continue to increase in speed until it reaches its terminal velocity. We can also observe this quantitatively. Imagine that we have an object falling from a cliff. At initial, the velocity is 0, acceleration is -10 m/s^2(rounded for simplicity). After one second, we can calculate the velocity. V= V(o) + a(t) V = 0 +(-10)(1) -10 m/s. The speed is just the magnitude of the velocity, or + 10 m/s. To prove that it will increase even more in speed (even though it already from from 0 m/s speed to 10 m/s speed with negative acceleration), here's another example to further the point which expands on the problem already given. Let's evaluate speed at 2 seconds. V= V(o) + a(t) V= 0 + (-10)(2) V= -20 m/s. so speed = +20 m/s Hopefully you can see now that while velocity is decreasing, the magnitude of it, speed, is increasing, and that a falling object always has negative acceleration of about -10m/s^2.
Acceleration of gravity near the surface of the earth is 9.8 meters (32.2 feet) per second2. Downward velocity after 2 seconds = 19.2 meters (64.4 feet) per second.