Just divide the force by the amount of stretch.
spring constant k = force F divided by displacement x = 60/1.5 = 40 N/m
That would be a spring, which is stretched when you apply force to it. The spring used have a specific force constant, which means that an extension of the spring to a certain length is equal to a fixed amount of force.
Spring constant of an elastic material is the force applied per unit extension.
the relation between force (F) and elongation (x) is F = kx where k is the spring constant. The stiffer the spring, the higher the force needed to get a certain elongation; or, for a given force, the elongation will be less for a stiffer spring
The larger the force pulling on a spring, the greater the length in the spring and the more energy that is stored in that spring. When looking at a spring there is a gradient that determines how much force much be used to sqeeze or stretch a spring a given amount. When a spring is stretched, the greater the force that is applied, the greater the change in length of the spring and the greater the amount of energy that is stored in the spring. A link is supplied to the Wikipedia article on the spring (device).
6.3
That would be a spring, which is stretched when you apply force to it. The spring used have a specific force constant, which means that an extension of the spring to a certain length is equal to a fixed amount of force.
Spring constant of an elastic material is the force applied per unit extension.
F = - k x In this equation, x is the distance that the spring has been stretched or compressed away from its equilibrium position F is the restoring force exerted by the spring. k is the spring constant.
The ratio of force applied to how much the spring streches (or compresses). In the SI, the spring constant would be expressed in Newtons/meter. A larger spring constant means the spring is "stiffer" - more force is required to stretch it a certain amount.
It takes a larger force to compress or pull a spring the same distance as a spring with a smaller spring constant. This is shown in Hooke's law. x=F/k k---is the spring constant F---is the force applied to the spring x is the distance the spring has been compressed
the relation between force (F) and elongation (x) is F = kx where k is the spring constant. The stiffer the spring, the higher the force needed to get a certain elongation; or, for a given force, the elongation will be less for a stiffer spring
Because the tension applied to the spring is distributed evenly along its whole length.
The amount the spring is stretched is called the displacement.
You can find out how long a spring has been stretched/compressed by knowing it's elastic constant and the force the spring is exerting trying to go back to it's original shape. F=K*x (Moore's law) F is the force exerted by the spring. K is the elastic constant. X is the displacement of the end of the spring from it's normal position. You want to find x, x = F/K
it is a value unique for every spring and depends on the materials. it doesn't change if the characteristics of your spring don't. if we have a spring with k spring constant and cut it in 2, the resulting springs still have k spring constant. the spring force depends on the spring constant. this formula F=k*x gives the force applied to a body by a spring, when it hase been pulled by x from it's natural state.
Certainly there is a limit, considering that the object is not deformed by the power employed to compress or stretch.
The constant spring stiffness formula is the force applied to the spring equal to the stiffness times the distance it moved. F=kx. Depending on where your axis are, it could be negative.