Can't be solved without knowing what x and y are. You can factor out 6y though. The expression then becomes:
6y * squareroot(2xy)
X to the 3rd power
12.25b3/2
1st term is a perfect square 3rd term is a perfect square square root of 1st and 3rd term multiplied together then multiplied again by 2 to get the middle term
Plot the given points on a suitable graph paper and construct 2 opposite equilateral triangles which will give a 3rd vertex of (2+square root of 3, 2-square root of 12) or a 3rd vertex of (2-square root of 3, 2+square root of 12) and each equal length of the triangle is 2 times square root of 5
Exponents, such as 2 to the 3rd power or 4 to the 4th power.
Find the square root to the thousandth place (3rd decimal digit) and round it to 2 decimal places to give the square root in hundredths. If you want a fraction, convert the decimal hundredths to a fraction by putting them over 100 and simplifying.
A small number at the upper left of a radical sign means, what root you want to take. If there is no number, the number "2" is assumed (square root), meaning, "What number must I reais to the power 2, to get the number in the radical sign?" For example, the square root (or 2nd. root) of 100 is 10, since 10 to the power 2 = 100. As another example, the cubic root (3rd. root) of 125 is 5, since 5 to the power 3 = 125.
The 3rd root of 9 = 2.080084
√36x^3 = √(6^2)(x^2)x =6x√x
The number is not a whole number. It has many decimal places. The distance from 1st to 2nd and 2nd to 3rd is both 60 ft. Being a 45 45 90 degree triangle, both sixty foot baselines will equal 'x' while the answer will be X times the square root of 2. And 60 times the square root of 2 is 84.8528137... So basically, the distance from third to first is 84.8528137...feet. The distance from home to seccond is exactly the same.
The cube root of 729 to the 3rd power is 729
The magnitude of cos(135°) is the same as that of cos(45°) [cos(180° - 135°)], and the sign is negative because it is in the second quadrant of the Cartesian plane, so it's the reciprocal of the negative square root of two, about -0.707. The cosines of 2nd- and 3rd-quadrant angles are negative, and the sines of 3rd- and 4th-quadrant angles are negative.