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What is the standard enthalpy of formation of isopropanol?
n-butane: -140.7 kJ/mol (liq.) & -124.7 kJ/mol (gas)isobutane: -158.4 kJ/mol (liq.) & -134.5 kJ/mol (gas)
What is the different between iodine in enthalpy in atomisation and enthalp y of sublimation?
i believe that standard enthalpy change of atomisation is the enthalpy change that takes place when one mole of gaseous atoms is formed from its elements under standard conditions(which includes breaking of bonds between atoms within molecules), while for sublimation it only involves the change of states (from solid to liquid) with no intramolecular bonds broken.
Why is the enthalpy of sublimation is equal to the sum of enthalpy of fusion and enthalpy of vaporization?
Enthalpy is a state function, and to a first approximation does not depend on temperature. So the change in enthalpy to go from solid to a gas directly (sublimation) at some temperature is equal to the sum of the enthalpies associated with going from a solid to a liquid (fusion) and going from a liquid to a gas (vaporization) at other temperatures.
What is when a substance changes from a solid to a liquid?
The heat energy, or enthalpy, associated with a solid to liquid transition is the enthalpy of fusion and that associated with a solid to gas transition is the enthalpy of sublimation.
What is the standard enthalpy for sodium sulfate?
The standard enthalpy for sodium sulphate is -1387kJ/mol.
What is the enthalpy of N2 at standard conditions?
The enthalpy of N2 at standard conditions is 0 kJ/mol.
What is the relationship between the standard enthalpy of formation and the standard enthalpy of reaction in chemical reactions?
The standard enthalpy of formation is the energy change when one mole of a compound is formed from its elements in their standard states. The standard enthalpy of reaction is the energy change for a reaction under standard conditions. The relationship between the two is that the standard enthalpy of reaction is the sum of the standard enthalpies of formation of the products minus the sum of the standard enthalpies of formation of the reactants.
What is the standard enthalpy of formation for N2 gas?
The standard enthalpy of formation for N2 gas is 0 kJ/mol.
What do the symbols mean Delta Hr Hf Hc Hn Ha in chemistry btw i know theyre enthalpy changes?
delta Hr is the enthalphy change of a reaction delta Hf is the enthalpy of formation where one mole of a substance is formed ( generally in its naturally occurring physical state) delta Hc is the enthalpy of combustion where one mole of a substance in its standard state undergoes combustion delta Hn is the enthalpy of neutralization where one mole of H+ reacts with OH- to form one mole of H2O delta Ha is the enthalpy of atomization where a molecule splits to form its neutral atomic components
How do you calculate enthalpy of formation of Cl2NNF2(g)?
To calculate the enthalpy of formation of Cl2NNF2(g), you can use the standard enthalpy of formation values of the reactants and products involved in the relevant chemical reaction. The enthalpy of formation is determined by the equation: ΔH_f° = ΣΔH_f°(products) - ΣΔH_f°(reactants). You need to find the standard enthalpy of formation for Cl2NNF2(g) and the standard enthalpies of the elements in their standard states (Cl2, N2, and F2) to perform this calculation. If the standard enthalpy values are not available, you may need to use Hess's law and related reactions to derive the value indirectly.
Why does oxygen gas not have an enthalpy of formation but ozone does?
Oxygen gas (O2) does not have an enthalpy of formation because it is an element in its standard state, which has an enthalpy of formation of zero by definition. Ozone (O3), on the other hand, is a compound and has a defined enthalpy of formation because it is formed from its elements in their standard states.
What is the standard enthalpy change of vaporization for CDDT?
The standard enthalpy change of vaporization for CDDT (Clotrityl chloride) is approximately 42 kJ/mol.
