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Neon!
gaseous state
The formation of clouds
The rate of a chemical reaction depends on the medium in which the reaction occurs. It may make a difference whether a medium is aqueous or organic; polar or non-polar; or liquid, solid, or gaseous.
the reaction would shift to favor the side with the most moles of gas
5535kJ is the reaction that represents breaking all the bonds in gaseous benzene C6H6.
Standard Heat (Enthalpy) of Formation, Hfo, of any compound is the enthalpy change of the reaction by which it is formed from its elements, reactants and products all being in a given standard state.By definition, the standard enthalpy (heat) of formation of an element in its standard state is zero, Hfo = 0.Standard Molar Enthalpy (Heat) of Formation, Hmo, of a compound is the enthalpy change that occurs when one mole of the compound in its standard state is formed from its elements in their standard states.Standard Enthalpy (Heat) of Reaction, Ho, is the difference between the standard enthalpies (heats) of formation of the products and the reactants.Ho(reaction) = the sum of the enthalpy (heat) of formation of products - the sum of the enthalpy (heat) of formation of reactants: Ho(reaction) = Hof(products) - Hof(reactants)To calculate an Enthalpy (Heat) of Reaction:Write the balanced chemical equation for the reaction Remember to include the state (solid, liquid, gas, or aqueous) for each reactant and product.Write the general equation for calculating the enthalpy (heat) of reaction: Ho(reaction) = Hof(products) - Hof(reactants)Substitute the values for the enthalpy (heat) of formation of each product and reactant into the equation. Remember, if there are 2 moles of a reactant or product, you will need to multiply the enthalpy term by 2, if molar enthalpies (heats) of formation are used.Standard Enthalpy (Heat) of FormationExample: Standard Enthalpy (Heat) of Formation of WaterThe standard enthalpy (heat) of formation for liquid water at 298K (25o) is -286 kJ mol-1. This means that 286 kJ of energy is released when liquid water, H2O(l), is produced from its elements, hydrogen and oxygen, in their standard states, ie, H2(g) and O2(g).This reaction is written as:H2(g) + ½O2(g) -----> H2O(l) Hfo = -286 kJ mol-1The standard enthalpy (heat) of formation of water vapour at 298K (25o) is -242 kJ mol-1.This means that 242 kJ of energy is released when gaseous water (water vapour), H2O(g), is produced from its elements, hydrogen and oxygen, in their standard states, ie, H2(g) and O2(g).This reaction is written as:H2(g) + ½O2(g) -----> H2O(g) Hfo = -242 kJ mol-1
Franck Meunier has written: 'Sources of uncertainty in the chromotropic acid method for gaseous formaldehyde determination'
Products of a chemical reaction are solids, liquids or gaseous.
Gaseous material
Vapour is not a chemical reaction; instead, it is a tangible substance in a gaseous state and has no necessary association with chemical reaction at all.
its a chemical reaction. in addition to heat and light, a new gaseous substances are formed
Neon!
gaseous state
2c2h6 + 7o2 ---> 4co2 + 6h2o
As you may soon learn in thermodynamics, the reaction rate constant, k, depends on the activation energy, temperature and pressure (if gaseous) of the system. Therefore, to unify reaction rates and rate constants, a standard temperature and pressure (such as STP and SATP) is designated to make sure when one chemist publishes a certain set of results, it could be accurately reproduced using the exact same reaction circumstances.
The formation of clouds