Points: (k, 3h) and (3k, h)
Slope: (h-3h)/3k-k) = -2h/2k => -h/k
Equation: y-3h = -h/k(x-k) => ky-3hk = -hx+hk => ky = -hx+4hk
Equation in its general form: hx+ky-4hk = 0
In coordinated geometry the points on a straight line will determine its equation.
Points: (0, -4) and (4, 8) Slope: -4-8 divided by 0-4 = 3 Use either of the points to find the equation as follows:- Equation: y--4 = 3(x-0) => y = 3x-4 Equation: y-8 = 3(x-4) => y = 3x-4
They could be the coordinates of a straight line equation
It is the set of points satisfying a linear equation.
alternatives to determine the equation straight line through two points?
Class point
Yes, when they are the coordinates of a straight line equation.
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
The solution of a linear equation in two variable comprises the coordinates of all points on the straight line represented by the equation.
Points: (-1, 6) and (2, -6) Slope: -4 Equation: y = -4x+2
So that you can plot out the points of a straight line on graph paper.
The equation will be a perpendicular bisector equation of the given points:- Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular equation: y--1 = -1/8(x--3/2) => y = -1/8x-3/16-1 Therefore the perpendicular bisector equation is: y = -1/8x -19/16