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ma + mb = m(a + b)
this is an algebra formule,
what cyfers, NUMBERS STAND A and M for
I suspect that slashes representing fractions are missing:
m/a + m/b = mb + ma/ab
= m(b + a)/ab
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∙ 11y ago
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What is the sum of mA and m B?
It is mA + mB
How do you prove that the exterior angle of a triangle is equal to the sum of the two opposite interior angles?
Assume a triangle ABC with a line AB (containing the side AB) with external angle D which is formed when line AB and line segment AC intersect. We are asked to prove that the external angle D is equal to the sum of the two interior angles B and C. Angles A and D are supplementary angles (they sum to 180 degrees) because they are linear angles (both together make a straight line, or a 180 degree angle). This means: m<A + m<D = 180 degrees. m<A = 180 deg - m<D Then because A, B, and C are the three angles in a triange: m<A + m<B + m<C = 180 deg m<A = 180 deg - m<B - m<C By substituting 180 deg - m<D in for m<A in the above equation we get: 180 deg - m<D = 180 deg - m<B - m<C Subtract 180 deg from each side: -m<D = -m<B - m<C Multiply both sides by -1 m<D = m<B + m<C Which proves that the measure of the external angle D is equal to the sum of the two opposite interior angles B and C for any given triangle. wow. that's a lot. lol.
What is the sum of b and 5?
(b+5)
What is the sum and difference of the same two terms?
Assuming that a and b are two non-negative numbers, then their sum is a + b and the difference is |a - b|.
How do you write a C-program for matrix multiplication?
it would have a part in it like this: for (i=0; i<n; ++i) { . for (j=0; j<l; ++j) { . . sum= 0; . . for (k=0; k<m; ++k) { . . . sum += a[i][k] * b[k][j]; . . } . . c[i][j] = sum; . } }
What is the sum of mA and m B?
It is mA + mB
The sum of 38 and m?
Sum = 38 + M
How do you prove that the exterior angle of a triangle is equal to the sum of the two opposite interior angles?
Assume a triangle ABC with a line AB (containing the side AB) with external angle D which is formed when line AB and line segment AC intersect. We are asked to prove that the external angle D is equal to the sum of the two interior angles B and C. Angles A and D are supplementary angles (they sum to 180 degrees) because they are linear angles (both together make a straight line, or a 180 degree angle). This means: m<A + m<D = 180 degrees. m<A = 180 deg - m<D Then because A, B, and C are the three angles in a triange: m<A + m<B + m<C = 180 deg m<A = 180 deg - m<B - m<C By substituting 180 deg - m<D in for m<A in the above equation we get: 180 deg - m<D = 180 deg - m<B - m<C Subtract 180 deg from each side: -m<D = -m<B - m<C Multiply both sides by -1 m<D = m<B + m<C Which proves that the measure of the external angle D is equal to the sum of the two opposite interior angles B and C for any given triangle. wow. that's a lot. lol.
The sum of 3 times m and n?
the sum of 3 times m and n
How do you Work out average speeds for drag cars?
You record the various speed on the same distance and sum it. Then divide that sum with how many times you record it. Like for x meters : 1. a m/s 2. b m/s 3. c m/s . . n. y m/s The average would be : (a+b+c +...y)/n
what id the sum of m and 6?
The sum of "m" and 6 is "m + 6".
What about nested for loop?
Possible. Example: void mat_mul (int m, int n, int l, const int **a, const int **b, int **c) { int i, j, k; double sum; for (i=0; i<m; ++i) { for (j=0; j<l; ++j) { sum= 0; for (k=0; k<n; ++k) { sum += a[i][k] * b[k][j]; } c[i][j]= sum; } }
The sum of two numbers is 12. The sum of the squares of the same two numbers is 90. What are the two numbers?
We get a system of equations: a+b=12 a2+b2=90. Replace 12-a for b, and we get: a2+(12-a)2=90 2a2-24a+144=90 2a2-24a+54=0 a2-12a+27=0 a1=9 a2=3 Because of symmetry, we get two equivalent solutions: a=9, b=3 or a=3,b=9
Write a c program that multiplies two numbers by repeated subtraction?
int mul (int a, int b) { int sum= 0; for (; b>0; --b) sum -= -a; for (; b<0; ++b) sum -= a; return sum; }
The sum of m and 9?
the sum of m and 9 is 9+m
What is the sum Of?
The sum of is the total of everything being summed; the sum total. Thus the sum of a, b and c is therefore a + b + c.
Why is the sum of an even and odd number alsways odd?
A number a is even if there exists an integer n such that a = 2n A number b is odd if there exists an integer m such that b = 2m + 1. So: a+b = (2n) + (2m +1) = 2 (n+m) + 1 Since n and m are integers, n+m is also an integer. So a+b satisfies the definition of an odd number.
