The sum of the oxidation numbers of all the atoms in C6H5CHO is equal to zero. This is because in a neutral molecule like C6H5CHO, the total oxidation number must balance out to zero.
The sum of the oxidation numbers of all carbons in C6H5CHO is equal to 0. This is because the oxidation number of carbon is -2 in CH3CHO, and there are six carbons in C6H5CHO. So, 6 * (-2) = -12. However, since the overall charge of the molecule is 0, the sum of the oxidation numbers of all carbons must be 0 to balance the charge.
In a neutral compound, the sum of oxidation numbers of all atoms will be zero. In a polyatomic ion, the sum of oxidation numbers of all atoms will be equal to the charge of the ion. The oxidation number of an element in its elemental form is zero. Fluorine always has an oxidation number of -1 in compounds. Oxygen usually has an oxidation number of -2 in compounds.
The oxidation number for hydrogen (H) is +1. Since there are 5 hydrogen atoms in H5P3O10, the total oxidation number contributed by hydrogen is +5. The sum of the oxidation numbers for all the atoms in a neutral compound is zero, so the sum of the oxidation numbers in H5P3O10 must also be zero. Therefore, the oxidation number of phosphorus (P) in H5P3O10 is +5.
The oxidation number of phosphorus in P4O6 is +3. This is because the sum of the oxidation numbers of all atoms in P4O6 must equal the overall charge of the compound, which is zero. The four phosphorus atoms each have an oxidation number of +3, as oxygen is usually assigned an oxidation number of -2 and there are a total of six oxygen atoms in the compound.
The oxidation number of Na in Na2S is +1. The oxidation number of S is -2. The sum of the oxidation numbers of all atoms in a compound must equal zero.
The sum of the oxidation numbers of all carbons in C6H5CHO is equal to 0. This is because the oxidation number of carbon is -2 in CH3CHO, and there are six carbons in C6H5CHO. So, 6 * (-2) = -12. However, since the overall charge of the molecule is 0, the sum of the oxidation numbers of all carbons must be 0 to balance the charge.
In a neutral compound, the sum of oxidation numbers of all atoms will be zero. In a polyatomic ion, the sum of oxidation numbers of all atoms will be equal to the charge of the ion. The oxidation number of an element in its elemental form is zero. Fluorine always has an oxidation number of -1 in compounds. Oxygen usually has an oxidation number of -2 in compounds.
The oxidation number for hydrogen (H) is +1. Since there are 5 hydrogen atoms in H5P3O10, the total oxidation number contributed by hydrogen is +5. The sum of the oxidation numbers for all the atoms in a neutral compound is zero, so the sum of the oxidation numbers in H5P3O10 must also be zero. Therefore, the oxidation number of phosphorus (P) in H5P3O10 is +5.
The oxidation number of phosphorus in P4O6 is +3. This is because the sum of the oxidation numbers of all atoms in P4O6 must equal the overall charge of the compound, which is zero. The four phosphorus atoms each have an oxidation number of +3, as oxygen is usually assigned an oxidation number of -2 and there are a total of six oxygen atoms in the compound.
The oxidation number of Na in Na2S is +1. The oxidation number of S is -2. The sum of the oxidation numbers of all atoms in a compound must equal zero.
The oxidation state of Cl in ClO2 is +3. This is determined by assigning oxygen an oxidation state of -2 and knowing that the overall charge of the compound is 0. Since there are two oxygen atoms with an oxidation state of -2 each, the oxidation state of Cl must be +3 to balance it out.
The oxidation number of osmium in OsO3F2 is +6. In osmium trioxide (OsO3), each oxygen atom has an oxidation number of -2, so the sum of oxidation numbers of all atoms in the compound must equal the charge of the compound which is zero. Since there are two fluorine atoms each with an oxidation number of -1 in OsO3F2, the oxidation number of osmium must be +6 to balance the charges.
-1 for Carbon (in carbide) and +2 for Ca
The oxidation number for O in O3 is -2. In O3, the total charge is 0 because it is a neutral molecule, and the sum of the oxidation numbers of all the atoms in O3 must equal 0. Since there are 3 oxygen atoms in O3, each with an oxidation number of -2, the total charge balances out.
The oxidation numbers for H, O, and P in H3PO4 are +1, -2, and +5, respectively. This can be determined by assigning variable oxidation states to the atoms in the molecule based on known rules and maintaining overall charge neutrality.
The sum of the oxidation numbers in the phosphate ion (PO4^3-) is -3. Each oxygen atom has an oxidation number of -2, totaling -8. The oxidation number for phosphorus is +5 to offset the oxygen atoms and give a total charge of -3 for the ion.
To find the oxidation number or charge of a polyatomic ion, consider the known charges of the individual atoms within the ion. For example, in the sulfate ion (SO4)2-, oxygen typically has an oxidation number of -2, and sulfur would then have an oxidation number to balance the charge of the ion. The sum of the oxidation numbers of all the atoms in the ion should equal the overall charge of the ion.