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To find the oxidation number or charge of a polyatomic ion, consider the known charges of the individual atoms within the ion. For example, in the sulfate ion (SO4)2-, oxygen typically has an oxidation number of -2, and sulfur would then have an oxidation number to balance the charge of the ion. The sum of the oxidation numbers of all the atoms in the ion should equal the overall charge of the ion.
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What is the oxidation no Of S In s4o6-2?
To determine the oxidation number of sulfur (S) in the polyatomic ion S4O6^2-, we can set up an equation where the sum of the oxidation numbers equals the charge of the ion. In this case, the total charge is -2. Each oxygen atom has an oxidation number of -2, so the total oxidation number contributed by oxygen is -12. To solve for sulfur, we set up the equation: 4x + 6(-2) = -2, where x is the oxidation number of sulfur. By solving this equation, we find that the oxidation number of sulfur in S4O6^2- is +5.
What is the oxidation number for Br in BrO3-?
If Br had an oxidation number of +7, the net charge on the ion would be +1, and not -1. Thus, the oxidation number for Br in BrO3- should be 5+.
How to calculate the oxidation number?
To calculate the oxidation number of an element in a compound, follow these steps: 1. Assign known oxidation numbers, such as +1 for hydrogen and -2 for oxygen. 2. Use algebraic rules to solve for the unknown oxidation number based on the compound's overall charge or known oxidation numbers of other elements. 3. Remember that the sum of oxidation numbers in a compound equals zero, or equals the compound's net charge if it is an ion.
What is the oxidation number of n in NO2F?
The oxidation number of oxygen is typically -2, and the oxidation number of fluorine is -1. Since the overall molecule NO2F has a neutral charge, we can set up the equation x + 2(-2) + (-1) = 0 to solve for the oxidation number of nitrogen. This gives us x = +4, indicating that the oxidation number of nitrogen in NO2F is +4.
Oxidation no of C in Fe CN 6 -3?
The oxidation number of carbon in Fe(CN)6^3- is -3. To find this, you can set up the equation where the total charge of the complex ion equals the sum of the oxidation numbers of each element in the ion and solve for the unknown oxidation number.
What is the oxidation no Of S In s4o6-2?
To determine the oxidation number of sulfur (S) in the polyatomic ion S4O6^2-, we can set up an equation where the sum of the oxidation numbers equals the charge of the ion. In this case, the total charge is -2. Each oxygen atom has an oxidation number of -2, so the total oxidation number contributed by oxygen is -12. To solve for sulfur, we set up the equation: 4x + 6(-2) = -2, where x is the oxidation number of sulfur. By solving this equation, we find that the oxidation number of sulfur in S4O6^2- is +5.
What is the oxidation number for Br in BrO3-?
If Br had an oxidation number of +7, the net charge on the ion would be +1, and not -1. Thus, the oxidation number for Br in BrO3- should be 5+.
How to calculate the oxidation number?
To calculate the oxidation number of an element in a compound, follow these steps: 1. Assign known oxidation numbers, such as +1 for hydrogen and -2 for oxygen. 2. Use algebraic rules to solve for the unknown oxidation number based on the compound's overall charge or known oxidation numbers of other elements. 3. Remember that the sum of oxidation numbers in a compound equals zero, or equals the compound's net charge if it is an ion.
What is the oxidation number of n in NO2F?
The oxidation number of oxygen is typically -2, and the oxidation number of fluorine is -1. Since the overall molecule NO2F has a neutral charge, we can set up the equation x + 2(-2) + (-1) = 0 to solve for the oxidation number of nitrogen. This gives us x = +4, indicating that the oxidation number of nitrogen in NO2F is +4.
Oxidation no of C in Fe CN 6 -3?
The oxidation number of carbon in Fe(CN)6^3- is -3. To find this, you can set up the equation where the total charge of the complex ion equals the sum of the oxidation numbers of each element in the ion and solve for the unknown oxidation number.
WHAT IS THE OXIDATION NUMBER in Bi(OH)3?
The oxidation number of Bi in Bi(OH)3 is +3. Oxygen generally has an oxidation number of -2, and since there are three hydroxide (OH-) ions, each with a -1 charge, the oxidation number of Bi can be calculated as follows: x + 3(-2) + 3(-1) = 0. Solve for x to get x = +3.
What's the oxidation number of cr in k2cro4?
6. To determine this the CrO4 ion must be 2- as it is balanced by 2 potassium ions which can only have a +1 charge. The oxygen atoms are considered to be present as O2- so all four contribute 8-. As the net charge is only 2- then chromium must have charge (oxidation number or state) of 6+.
What is the oxidation number of b in the compound b4 o7?
The oxidation number of B in B4O7 is +3. This can be determined by assigning oxygen an oxidation number of -2, then setting up an equation to solve for the oxidation number of B.
How do you assign oxidation numbers fo scn?
To assign oxidation numbers for SCN-, first we assign oxidation number x to S. Then, we know that the overall charge of SCN- is -1, and N is -3 in most cases. By summing up the oxidation numbers (-1), we can solve for x as +2.
What is the oxidation number for P in H3P2O7?
The oxidation number of Phosphorus (P) in H3P2O7 is +5. This can be determined by assigning hydrogen an oxidation number of +1 and oxygen an oxidation number of -2, then setting up an equation to solve for the unknown oxidation number of Phosphorus.
What is the oxidation number of CuHSO4?
The oxidation number of Cu in CuHSO4 is +1. This is because the overall charge of the compound is 0, and the oxidation number of H is +1, S is +6, and O is -2. By calculating the total oxidation numbers and assigning x to Cu, you can solve for x to find that Cu is in the +1 oxidation state.
How do you solve for the oxidation number of a chlorate ion?
The chlorate ion is ClO3-. Some text books say that the oxidation number of the whole ion is equal to the charge, so in this cas it would be -1. However most teachers would sya that oxidation numbers only refer to atoms. So working out the oxidation numbers:- oxygen is -2, (using the rule, or if you use the he electronegativity method- gives the same answer as O is more electronegatoive than Cl) the sum of oxidation numbers of Cl and O are -1 (the charge on the ion) - I'll call the oxidation number of Cl OxCl -1 =OxCl + (3* -2)= OxCl -6 therefore OxCl = +5
