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To determine the oxidation number of sulfur (S) in the polyatomic ion S4O6^2-, we can set up an equation where the sum of the oxidation numbers equals the charge of the ion. In this case, the total charge is -2. Each oxygen atom has an oxidation number of -2, so the total oxidation number contributed by oxygen is -12. To solve for sulfur, we set up the equation: 4x + 6(-2) = -2, where x is the oxidation number of sulfur. By solving this equation, we find that the oxidation number of sulfur in S4O6^2- is +5.
What else can I help you with?
What is the oxidation number for BaSO4?
The oxidation number for BaSO4 is 6. It goes as follows: +2 for Ba +6 for S -2 for O
What is the oxidation number for s2cl2?
The oxidation number of S in S2Cl2 is +1. Each Cl atom has an oxidation number of -1, and since the molecule is neutral, the overall oxidation numbers of S must balance out to zero. Thus, the oxidation number of S in this compound is +1.
What is the oxidation number of SO2?
Oxidation state of O is -2.Oxidation state of S is +4.
What is the product when thiosulfate ions and iodine react?
2 S2O32- + I2 --> S4O62- + 2 I-thiosulfate + iodine -> tetrathionate* + iodide* -O3=-=S-S-S-S=-=O3-
What is the oxidation number of S in Li2SO4?
The oxidation number of sulfur (S) in Li2SO4 is +6. This is because lithium (Li) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, which allows us to calculate the oxidation number of sulfur.
Balancing and after balancing?
s2o32-to give s4o62-
What is the oxidation number for BaSO4?
The oxidation number for BaSO4 is 6. It goes as follows: +2 for Ba +6 for S -2 for O
What is the oxidation number for s2cl2?
The oxidation number of S in S2Cl2 is +1. Each Cl atom has an oxidation number of -1, and since the molecule is neutral, the overall oxidation numbers of S must balance out to zero. Thus, the oxidation number of S in this compound is +1.
What is the oxidation of SO2?
S = +4 oxidation state O = -2 oxidation state
What is the oxidation number of SO2?
Oxidation state of O is -2.Oxidation state of S is +4.
What is oxidation state of S in S in S2O32?
The oxidation state of sulfur in a thiosulfate ion is + 2.
What is the oxidation of the of s in the compound so2?
Sulphar has +4 oxidation state.Oxygen has -2 oxidation state.
What is the product when thiosulfate ions and iodine react?
2 S2O32- + I2 --> S4O62- + 2 I-thiosulfate + iodine -> tetrathionate* + iodide* -O3=-=S-S-S-S=-=O3-
What is the oxidation number of S in Li2SO4?
The oxidation number of sulfur (S) in Li2SO4 is +6. This is because lithium (Li) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, which allows us to calculate the oxidation number of sulfur.
In CaSO4 the oxidation number of Ca is that of S is and that ofO is?
In CaSO4, the oxidation number of Ca is +2, the oxidation number of S is +6, and the oxidation number of O is -2.
What is the oxidation number of sulfur in the tetrathionate ion S4O62-?
In the tetrathionate ion (S4O6)2-, the total charge of the ion is 2-. Each oxygen atom has an oxidation number of -2, totaling -12 for all six oxygen atoms. Since the overall charge is 2-, the sum of the oxidation numbers of sulfur atoms must equal +2. With four sulfur atoms present, each sulfur atom in the tetrathionate ion has an oxidation number of +6.
Does s8 always have an oxidation of 4?
The oxidation number of S in S8 is ZERO!
