The oxidation number of S in S8 is ZERO!
The oxidation number of an atom in it's elemental state is always 0.
Oxidation number is a concept that refers to atoms not molecules. The oxidation number of S in S8 is zero. The oxidation number of an atom in the pure element is always 0. S8 is a form of sulfur, the most commonly encountered , there are many other forms (allotropes). The oxidation number of S in any of its allotrpes is zero.
The oxidation number of S in S8 is 0. Each sulfur atom in S8 has an oxidation number of 0 because it is in its elemental form and not bonded to any other element.
Zero
It's an Oxidation-reduction
The oxidation of sulfur can result in various oxidation states, including -2, 0, +4, and +6. Sulfur can form compounds like sulfur dioxide (SO2) in the +4 oxidation state and sulfuric acid (H2SO4) in the +6 oxidation state.
In nature generally they are S8 molecules. It shows zero in that molecule.
In nature generally they are S8 molecules. It shows zero in that molecule.
The oxidation number of sulfur in sulfur powder (S8) is 0. Each sulfur atom in the elemental form has an oxidation number of 0.
There are s8 sulfur molecules. It shows 0 oxidation number.
generally sulphur shows many numbers. It has 0 in S8 molecules.
The oxidation number of carbon in Na2CO3 is +4. This is because the oxidation numbers of sodium and oxygen are always +1 and -2, respectively, and the sum of the oxidation numbers in a compound must equal zero.