Sulfur can have a wide range of oxidation in its compounds
-2 in H2S
0 in elementary sulfur (S8)
+4 in SO2
+6 in SO3
In HSO4- sulfur's oxidation state is +5.
elemental sulfur is not oxidised. It has to be in some sort of compound. For example, in H2S, the sulfur has an oxidation state of -2. Each hydrogen has a +1, so if they are removed, it decreases the overall charge. Remove two, and the charge is decreased by 2, making it -2.
The oxidation number of Sulfur (S) in Na2S2O3 is +2. This is because the overall charge of the compound is zero, and since each Sodium (Na) atom has an oxidation state of +1, the oxidation state of Sulfur must be +2 to balance the charges in the compound.
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
Sulfur has an oxidation state of +4 in SO3^2-. Each oxygen atom has an oxidation state of -2.
For CaSO4 (calcium sulfate), the oxidation number of sulfur is +6. For SO4 (sulfate ion), the oxidation number of sulfur is +6. For SO2 (sulfur dioxide), the oxidation number of sulfur is +4. For SO3 (sulfur trioxide), the oxidation number of sulfur is +6.
There are s8 sulfur molecules. It shows 0 oxidation number.
The oxidation state of sulfur in SO2 is 4.
Yes, when sulfur reacts with oxygen to form sulfur dioxide (SO2), it is an oxidation reaction because sulfur gains oxygen atoms. The sulfur undergoes oxidation, increasing its oxidation state from 0 to +4.
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2, so by the rules of oxidation numbers, sulfur must have an oxidation number of +6 to balance the equation.
In SO3^2-, sulfur has an oxidation state of +4 (Sulfur's typical oxidation state is +6 and each oxygen has an oxidation state of -2, so the total charge of the ion of -2 corresponds to sulfur being in a +4 oxidation state).
The oxidation number of sulfur in sulfur powder (S8) is 0. Each sulfur atom in the elemental form has an oxidation number of 0.
The oxidation number of sulfur can vary depending on the compound it is in. In most cases, sulfur has an oxidation number of -2, as seen in hydrogen sulfide (H2S) or sulfur dioxide (SO2). However, in some compounds such as sulfuric acid (H2SO4), sulfur can have an oxidation number of +6.
Since the total molecule must have zero net oxidation state and there are two oxygen atoms but only one sulfur atom, the sulfur must have oxidation state +4.
Hydrogen sulfide (H2S) is a compound that contains sulfur with an oxidation number of -2. In this compound, sulfur is bonded to two hydrogen atoms, each contributing a +1 oxidation state, resulting in a total oxidation state of -2 for sulfur.
The oxidation state of sulfur in MgSO4 is +6. This is because magnesium has an oxidation state of +2 and oxygen typically has an oxidation state of -2, so the overall compound must have a net charge of 0, leading to sulfur having an oxidation state of +6 to balance the charges.
The oxidation number of sulfur (S) in SO2 is +4. Each oxygen atom has an oxidation number of -2, so in order to balance the charges, sulfur must have an oxidation number of +4.