In HSO4- sulfur's oxidation state is +5.
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+5
S has an oxidation state of +4 in a sulfite anion as stated. In oxyanions, oxygen always has an oxidation state of -2. Therefore, three oxygen atoms will have total oxidation number of -6, requiring an oxidation number of +4 for sulfur to sum to the charge of -2 on the anion as a whole.
Sodium Oxide, or NaOH, has no oxidation state. It has a charge, which is zero. The elements that make up NaOH, however, do have oxidation states. The oxidation state of sodium (Na) is +1, and it will forever be +1 because it is impossible for it to be anything else, no matter what situation. The same applies for Hydrogen. Oxygen has an oxidation state of -2, and almost always will have an oxidation state of -2. There is one notable exception: H2O2. In this case, since the total charge of the compound is neutral and the oxidation state of Hydrogen must be +1 and, seeing as there are two hydrogens, bringing the overall charge up to 2, the oxidation state of oxygen must be -1. If it was -2, then the molecule would have an overall charge of -2.
SO42- (our goal is to get -2 charge) Oxygen by default has a -2 oxidation number, and we have 4 total, -2 X 4 = -8, our goal is -2, so S is +6.
+2
Things are complicated if we use the term valency. It is better to use the term Oxidation state or Oxidation Number. In SO2, the oxidation state of sulphur is +4 and In SO3, the oxidation state of sulphur is +6.
In HSO4- sulfur's oxidation state is +5.
Oxidation state of O is -2.Oxidation state of S is +4.
S = +4 oxidation state O = -2 oxidation state
The oxidation state of sulfur in a thiosulfate ion is + 2.
The oxidation state of sulfur in a thiosulfate ion is + 2.
The oxidation state of S in HgS is -2. Since Hg is +2, to make a neutral charge S must be -2.
Sulphar has +4 oxidation state.Oxygen has -2 oxidation state.
S = +2 oxidation state Cl = -1 oxidation state
+2
Oxidation state: +2
S has an oxidation state of +4 in a sulfite anion as stated. In oxyanions, oxygen always has an oxidation state of -2. Therefore, three oxygen atoms will have total oxidation number of -6, requiring an oxidation number of +4 for sulfur to sum to the charge of -2 on the anion as a whole.
S has an oxidation state of +4 in a sulfite anion as stated. In oxyanions, oxygen always has an oxidation state of -2. Therefore, three oxygen atoms will have total oxidation number of -6, requiring an oxidation number of +4 for sulfur to sum to the charge of -2 on the anion as a whole.