In the thiosulfate ion (S₂O₃²⁻), the oxidation state of sulfur (S) can be determined by considering the overall charge and the oxidation states of oxygen. Oxygen typically has an oxidation state of -2. In S₂O₃²⁻, there are three oxygen atoms contributing a total of -6. To balance the -2 charge of the ion, the total oxidation state of the two sulfur atoms must be +4. Therefore, the average oxidation state of sulfur in S₂O₃²⁻ is +2, but one sulfur is usually assigned an oxidation state of +6 and the other -2.
S = +4 oxidation state O = -2 oxidation state
The oxidation state of sulfur in a thiosulfate ion is + 2.
The oxidation state of S in HgS is -2. Since Hg is +2, to make a neutral charge S must be -2.
Sulphar has +4 oxidation state.Oxygen has -2 oxidation state.
+2
The oxidation number of sulfur (S) in S2O3 is +2. This is because oxygen always has an oxidation number of -2, and since there are three oxygen atoms in S2O3, the total oxidation number of oxygen will be -6. The sum of the oxidation numbers in the compound must equal zero, so the oxidation number of sulfur is +2.
The oxidation state of sulfur in the thiosulfate ion (S2O3^2-) is +2. Each oxygen contributes -2 charge, so the overall charge of -2 in the ion is balanced by the +2 charge on sulfur.
S = +4 oxidation state O = -2 oxidation state
The oxidation state of sulfur in a thiosulfate ion is + 2.
Oxidation state of O is -2.Oxidation state of S is +4.
The oxidation number for BaSO4 is 6. It goes as follows: +2 for Ba +6 for S -2 for O
The oxidation state of S in HgS is -2. Since Hg is +2, to make a neutral charge S must be -2.
Sulphar has +4 oxidation state.Oxygen has -2 oxidation state.
The oxidation state of sulfur in SO2Cl2 is +4. In this molecule, each oxygen atom has an oxidation state of -2, each chlorine atom has an oxidation state of -1, and the overall charge of the molecule is 0, which means the oxidation state of sulfur must be +4 to balance the charges.
+2
S2O3: +2 for S KCl: +1 for K, -1 for Cl He: 0 Cl2: 0 CO3^2-: -2 for O, +2 for C NO3-: -2 for O, +5 for N NO2-: -2 for O, +4 for N H3N: -3 for H, +1 for N
The oxidation state of S in SO42- is +6. Each oxygen atom has an oxidation state of -2, so the total charge of -2 for sulfate ion requires sulfur to have an oxidation state of +6 to balance the charge.