S = +4 oxidation state O = -2 oxidation state
The oxidation state of sulfur in a thiosulfate ion is + 2.
The oxidation state of S in HgS is -2. Since Hg is +2, to make a neutral charge S must be -2.
Sulphar has +4 oxidation state.Oxygen has -2 oxidation state.
+2
The oxidation number of sulfur (S) in S2O3 is +2. This is because oxygen always has an oxidation number of -2, and since there are three oxygen atoms in S2O3, the total oxidation number of oxygen will be -6. The sum of the oxidation numbers in the compound must equal zero, so the oxidation number of sulfur is +2.
The oxidation state of sulfur in the thiosulfate ion (S2O3^2-) is +2. Each oxygen contributes -2 charge, so the overall charge of -2 in the ion is balanced by the +2 charge on sulfur.
S = +4 oxidation state O = -2 oxidation state
The oxidation state of sulfur in a thiosulfate ion is + 2.
Oxidation state of O is -2.Oxidation state of S is +4.
The oxidation number for BaSO4 is 6. It goes as follows: +2 for Ba +6 for S -2 for O
The oxidation state of S in HgS is -2. Since Hg is +2, to make a neutral charge S must be -2.
Sulphar has +4 oxidation state.Oxygen has -2 oxidation state.
The oxidation state of sulfur in SO2Cl2 is +4. In this molecule, each oxygen atom has an oxidation state of -2, each chlorine atom has an oxidation state of -1, and the overall charge of the molecule is 0, which means the oxidation state of sulfur must be +4 to balance the charges.
+2
In HSO4- sulfur's oxidation state is +5.
The oxidation state of S in SO42- is +6. Each oxygen atom has an oxidation state of -2, so the total charge of -2 for sulfate ion requires sulfur to have an oxidation state of +6 to balance the charge.