0
The oxidation No. is '3'.
To calculate oxidation numbers, remember the 'yardstick' of oxygen at '-2' . There are a few exceptions to this, but work from '-2'.
S2O3
There being 3 x oxygen present, the the oxygen moiety is '3 x -2 = -6
So the sulphur moiety must be '+6', in order to maintain charge neutrality.
Hence 2 x S = 2 X x = 6
x = 3
So sulphur oxidation is '+3'.
What else can I help you with?
What is oxidation number of S2?
The oxidation number of S in S2 is -2. Because each S atom carries a charge of -1.
What is the oxidation number of S2 in h2s2o8?
In H2S2O8, sulfur (S) has an oxidation number of +6. This is determined by assigning hydrogen (H) an oxidation number of +1 and oxygen (O) an oxidation number of -2, and then calculating the oxidation number of sulfur accordingly.
What is the oxidation number of any monoatomic ions?
The oxidation number of any monoatomic ion is equal to the charge of the ion. For example, the oxidation number of the sodium ion (Na+) is +1, and the oxidation number of the chloride ion (Cl-) is -1.
What is the oxidation number charge of the ion?
The oxidation number of monoatomic ions is the same as their ion charge: +2 in Fe(II) for Fe2+, +3 in Fe(III) for Fe3+, -2 in sulfide S2-
What are the oxidation numbers for sulfide?
The oxidation number of sulfur in sulfide is -2. This is because in most compounds, such as sulfide (S2-), sulfur tends to gain two electrons to achieve a stable octet configuration.
What is oxidation number of S2?
The oxidation number of S in S2 is -2. Because each S atom carries a charge of -1.
What is the oxidation number of S2 in h2s2o8?
In H2S2O8, sulfur (S) has an oxidation number of +6. This is determined by assigning hydrogen (H) an oxidation number of +1 and oxygen (O) an oxidation number of -2, and then calculating the oxidation number of sulfur accordingly.
What is the oxidation number of any monoatomic ions?
The oxidation number of any monoatomic ion is equal to the charge of the ion. For example, the oxidation number of the sodium ion (Na+) is +1, and the oxidation number of the chloride ion (Cl-) is -1.
What is the oxidation state of S in S2 O3 2-?
+2
What is the oxidation number charge of the ion?
The oxidation number of monoatomic ions is the same as their ion charge: +2 in Fe(II) for Fe2+, +3 in Fe(III) for Fe3+, -2 in sulfide S2-
How do you name S2O3?
S2O3 is commonly known as thiosulfate.
What are the oxidation numbers for sulfide?
The oxidation number of sulfur in sulfide is -2. This is because in most compounds, such as sulfide (S2-), sulfur tends to gain two electrons to achieve a stable octet configuration.
What is the name for S2O3-2?
thiosulphate
What is the oxidation stage of S in S2O32-?
The oxidation state of sulfur in the thiosulfate ion (S2O3^2-) is +2. Each oxygen contributes -2 charge, so the overall charge of -2 in the ion is balanced by the +2 charge on sulfur.
What is the oxidation number for BaSO4?
The oxidation number for BaSO4 is 6. It goes as follows: +2 for Ba +6 for S -2 for O
What is the oxidation number for S in S 2?
Pure element has zero oxidation number. When forming ions it is equal the charge of ion.Atomic sulfur has oxidation number of 0. Its simple ion, sulfide carries oxidation status -2. While forming numerous compounds, the oxidation number of sulfur can vary form -2 to +6.
What compound is S2O3?
S2O3 is the chemical formula for thiosulfate ion. It is a polyatomic ion composed of two sulfur atoms and three oxygen atoms.
