0
What else can I help you with?
What is the oxidation state of S in S2O32?
The oxidation state of sulfur in S2O32- is +2 because each oxygen has an oxidation state of -2 and the overall charge of the molecule is -2. This means that the two sulfur atoms in S2O32- must have an oxidation state of +2 each in order to balance out the negative charge.
What is the change of oxidation number of sulphur during iodometric titration experiment?
In an iodometric titration experiment, the oxidation number of sulfur changes from -2 in the thiosulfate ion (S2O32-) to +4 in the sulfate ion (SO42-) as sulfur gains oxygen atoms. This change indicates the transfer of electrons and oxidation of sulfur during the reaction.
What is the oxidation number for s2cl2?
The oxidation number of S in S2Cl2 is +1. Each Cl atom has an oxidation number of -1, and since the molecule is neutral, the overall oxidation numbers of S must balance out to zero. Thus, the oxidation number of S in this compound is +1.
What is the oxidation number of SO2?
Oxidation state of O is -2.Oxidation state of S is +4.
What is the oxidation number of S in Li2SO4?
The oxidation number of sulfur (S) in Li2SO4 is +6. This is because lithium (Li) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, which allows us to calculate the oxidation number of sulfur.
What is oxidation state of S in S in S2O32?
The oxidation state of sulfur in a thiosulfate ion is + 2.
What is the oxidation state of S in S2O32?
The oxidation state of sulfur in S2O32- is +2 because each oxygen has an oxidation state of -2 and the overall charge of the molecule is -2. This means that the two sulfur atoms in S2O32- must have an oxidation state of +2 each in order to balance out the negative charge.
What is the change of oxidation number of sulphur during iodometric titration experiment?
In an iodometric titration experiment, the oxidation number of sulfur changes from -2 in the thiosulfate ion (S2O32-) to +4 in the sulfate ion (SO42-) as sulfur gains oxygen atoms. This change indicates the transfer of electrons and oxidation of sulfur during the reaction.
Balancing and after balancing?
s2o32-to give s4o62-
The first stage in the oxidation of a primary alcohol produces a?
aldehyde
What is the oxidation number for s2cl2?
The oxidation number of S in S2Cl2 is +1. Each Cl atom has an oxidation number of -1, and since the molecule is neutral, the overall oxidation numbers of S must balance out to zero. Thus, the oxidation number of S in this compound is +1.
What is the oxidation of SO2?
S = +4 oxidation state O = -2 oxidation state
What is the oxidation number of SO2?
Oxidation state of O is -2.Oxidation state of S is +4.
What is the oxidation of the of s in the compound so2?
Sulphar has +4 oxidation state.Oxygen has -2 oxidation state.
What is the oxidation number of S in Li2SO4?
The oxidation number of sulfur (S) in Li2SO4 is +6. This is because lithium (Li) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, which allows us to calculate the oxidation number of sulfur.
In CaSO4 the oxidation number of Ca is that of S is and that ofO is?
In CaSO4, the oxidation number of Ca is +2, the oxidation number of S is +6, and the oxidation number of O is -2.
Given that 31.6ml of 0.141M Na2S2O3 is needed to reach the stoichiometric point how many grams of Cl2 are in the titrated?
Thiosulfate: 2 S2O32- --> S4O62- + 2e-equivalency to:Chlorine: 1 Cl2 + 2e- --> 2Cl-31.6 ml * 0.141 mmol/ml S2O32- = 4.456 mmol S2O32-= 4.456 *(2 electron / 2 S2O32-) = 4.456 mmol (electrons) == 4.456 *(1 Cl2 / 2 electron) = 2.228 mmol Cl2 == 2.228 * 70.90 mg/mmol Cl2 = 158 mg == 0.158 g Chlorine
