If Br had an oxidation number of +7, the net charge on the ion would be +1, and not -1. Thus, the oxidation number for Br in BrO3- should be 5+.
Br is a non metal. Oxidation number of it is +7.
To get a net 1- charge, the oxidation number on Br would be 5+, since each oxygen is 2-
Oxidation number of Br in BrO3 is 6. BrO3 doesn't exist. It should actually be BrO3- ion with +5 oxidation number for Br.
BrO3 is an anion of minus one (-1) charge. BrO3^-1 Using oxygen as the standard at '-2' Then the oxygen moiety is 3 X -2 = -6 So doing a 'little' sum -6 + Br = -1 Add '6' to both sides Br = 5 (The oxidation number of Br). NB Using '-2' for oxygen is a good standard for most molecules/ions. However, oxygen's oxidation number does vary , but not in very many molecules/ions.
Each Oxygen has -2 number.Bromines oxidation number is +5.
LiBrO3 this decomposes to Li^(+) & BrO3^(-) The bromate anion has a charge of '-1' Use the standard for oxygen at '-2' Since there are 3 oxygens then the oxygen moiety is 3 X -2 = -6 Creating a little sum Br + -6( oxygen moiety) = -1( anion charge) Br - 6 = -1 Add '6 'to both sides Br = (+)5 The oxidation state of bromine.
Each Br atom has an oxidation number of zero.
Oxidation number of Br in BrO3 is 6. BrO3 doesn't exist. It should actually be BrO3- ion with +5 oxidation number for Br.
-2 for each O, +5 for Br
In the bromate ion (BrO3-) bromine is in the 5+ oxidation stae while the oxygen atoms are in the 2- oxidation state.
BrO3 is an anion of minus one (-1) charge. BrO3^-1 Using oxygen as the standard at '-2' Then the oxygen moiety is 3 X -2 = -6 So doing a 'little' sum -6 + Br = -1 Add '6' to both sides Br = 5 (The oxidation number of Br). NB Using '-2' for oxygen is a good standard for most molecules/ions. However, oxygen's oxidation number does vary , but not in very many molecules/ions.
Each Oxygen has -2 number.Bromines oxidation number is +5.
LiBrO3 this decomposes to Li^(+) & BrO3^(-) The bromate anion has a charge of '-1' Use the standard for oxygen at '-2' Since there are 3 oxygens then the oxygen moiety is 3 X -2 = -6 Creating a little sum Br + -6( oxygen moiety) = -1( anion charge) Br - 6 = -1 Add '6 'to both sides Br = (+)5 The oxidation state of bromine.
-2 for each O, +5 for Br
Each Br atom has an oxidation number of zero.
The Potassium (K) has an oxidation number of +1. The Bromine (Br) has an oxidation number of -1.
+1 for Na -1 for Br
Each Br atom has an oxidation number of zero.
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