If Br had an oxidation number of +7, the net charge on the ion would be +1, and not -1. Thus, the oxidation number for Br in BrO3- should be 5+.
The oxidation number of Br in BrO3 is +5. This is because the oxidation number of oxygen is usually -2, and since there are three oxygen atoms in BrO3, the total negative charge from oxygen is -6. To balance the charge of the compound which is neutral, the oxidation number of Br is therefore +5.
The oxidation number for Br in BrO3 is +5. This is because the overall charge of the BrO3 molecule is -1, and the oxygen atoms have an oxidation number of -2 each. Therefore, the oxidation number of Br must be calculated as +5 to balance the charges.
In the compound BrO3-, bromine is more electronegative than oxygen and has an oxidation number of +5 to satisfy the overall charge of the anion which is -1. Each oxygen atom has an oxidation number of -2, so the total oxidation numbers in BrO3- sum up to -1.
LiBrO3 this decomposes to Li^(+) & BrO3^(-) The bromate anion has a charge of '-1' Use the standard for oxygen at '-2' Since there are 3 oxygens then the oxygen moiety is 3 X -2 = -6 Creating a little sum Br + -6( oxygen moiety) = -1( anion charge) Br - 6 = -1 Add '6 'to both sides Br = (+)5 The oxidation state of bromine.
The oxidation number of Li in LiBr is +1, and the oxidation number of Br is -1.
The oxidation number of Br in BrO3 is +5. This is because the oxidation number of oxygen is usually -2, and since there are three oxygen atoms in BrO3, the total negative charge from oxygen is -6. To balance the charge of the compound which is neutral, the oxidation number of Br is therefore +5.
The oxidation number for Br in BrO3 is +5. This is because the overall charge of the BrO3 molecule is -1, and the oxygen atoms have an oxidation number of -2 each. Therefore, the oxidation number of Br must be calculated as +5 to balance the charges.
-2 for each O, +5 for Br
The oxidation number of Br in BrO3- is +5. This is because oxygen typically has an oxidation number of -2, and since there are three oxygen atoms in the BrO3- ion, the total negative charge is -6. Since the overall charge of the ion is -1, the oxidation number of Br must be +5 to balance the charges.
In the compound BrO3-, bromine is more electronegative than oxygen and has an oxidation number of +5 to satisfy the overall charge of the anion which is -1. Each oxygen atom has an oxidation number of -2, so the total oxidation numbers in BrO3- sum up to -1.
LiBrO3 this decomposes to Li^(+) & BrO3^(-) The bromate anion has a charge of '-1' Use the standard for oxygen at '-2' Since there are 3 oxygens then the oxygen moiety is 3 X -2 = -6 Creating a little sum Br + -6( oxygen moiety) = -1( anion charge) Br - 6 = -1 Add '6 'to both sides Br = (+)5 The oxidation state of bromine.
The oxidation number of Li in LiBr is +1, and the oxidation number of Br is -1.
The oxidation number of Br in ZnBr2 is -1. In ZnBr2, zinc (Zn) has an oxidation number of +2, so the two bromine (Br) atoms each have an oxidation number of -1 to balance the charge of the compound.
The oxidation number of Br in KBrO3 is +5. This is because oxygen typically has an oxidation number of -2 and the overall compound has a neutral charge. Since there is only one Br atom in KBrO3 and the oxidation numbers of K and O are known, the oxidation number of Br can be calculated as +5 to balance the overall charge.
-2 for each O, +5 for Br
The Potassium (K) has an oxidation number of +1. The Bromine (Br) has an oxidation number of -1.
+1 for Na -1 for Br