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The chlorate ion is ClO3-. Some text books say that the oxidation number of the whole ion is equal to the charge, so in this cas it would be -1. However most teachers would sya that oxidation numbers only refer to atoms. So working out the oxidation numbers:-
oxygen is -2, (using the rule, or if you use the he electronegativity method- gives the same answer as O is more electronegatoive than Cl)
the sum of oxidation numbers of Cl and O are -1 (the charge on the ion) - I'll call the oxidation number of Cl OxCl
-1 =OxCl + (3* -2)= OxCl -6
therefore OxCl = +5
What else can I help you with?
What is the oxidation number for oxygen in chlorate?
The oxidation number for oxygen in chlorate (ClO3-) is -2. This is due to the fact that the oxidation number of Cl (chlorine) in the chlorate ion is +5, and there are three oxygen atoms bonded to it.
How to solve for the oxidation number of charge of a polyatomic ion?
To find the oxidation number or charge of a polyatomic ion, consider the known charges of the individual atoms within the ion. For example, in the sulfate ion (SO4)2-, oxygen typically has an oxidation number of -2, and sulfur would then have an oxidation number to balance the charge of the ion. The sum of the oxidation numbers of all the atoms in the ion should equal the overall charge of the ion.
Oxidation no of C in Fe CN 6 -3?
The oxidation number of carbon in Fe(CN)6^3- is -3. To find this, you can set up the equation where the total charge of the complex ion equals the sum of the oxidation numbers of each element in the ion and solve for the unknown oxidation number.
What is the oxidation number of each ion in the compound MgBr2?
In MgBr2, the magnesium ion (Mg) has an oxidation number of +2, while the bromide ion (Br) has an oxidation number of -1.
What is the oxidation no Of S In s4o6-2?
To determine the oxidation number of sulfur (S) in the polyatomic ion S4O6^2-, we can set up an equation where the sum of the oxidation numbers equals the charge of the ion. In this case, the total charge is -2. Each oxygen atom has an oxidation number of -2, so the total oxidation number contributed by oxygen is -12. To solve for sulfur, we set up the equation: 4x + 6(-2) = -2, where x is the oxidation number of sulfur. By solving this equation, we find that the oxidation number of sulfur in S4O6^2- is +5.
What is the oxidation number for oxygen in chlorate?
The oxidation number for oxygen in chlorate (ClO3-) is -2. This is due to the fact that the oxidation number of Cl (chlorine) in the chlorate ion is +5, and there are three oxygen atoms bonded to it.
How to solve for the oxidation number of charge of a polyatomic ion?
To find the oxidation number or charge of a polyatomic ion, consider the known charges of the individual atoms within the ion. For example, in the sulfate ion (SO4)2-, oxygen typically has an oxidation number of -2, and sulfur would then have an oxidation number to balance the charge of the ion. The sum of the oxidation numbers of all the atoms in the ion should equal the overall charge of the ion.
What is the oxidation state of chlorine in the chlorate ion ClO3?
The oxidation state of chlorine in the chlorate ion ClO3 is +5. This is because oxygen is more electronegative than chlorine and its oxidation state is typically -2 in compounds. Since there are three oxygen atoms with a total charge of -6 in the chlorate ion, the oxidation state of chlorine must be +5 to balance out the charge.
Oxidation no of C in Fe CN 6 -3?
The oxidation number of carbon in Fe(CN)6^3- is -3. To find this, you can set up the equation where the total charge of the complex ion equals the sum of the oxidation numbers of each element in the ion and solve for the unknown oxidation number.
What is the charge of chlorate?
The charge on a chlorate ion is -1. This means that the oxidation state of the chlorine atom in the ion is +7. Cl + O3 = -1 (overall charge) ? + (3 x -2) = -1 Therefore ?= +7 You must remember to put in the sign, even if it is positive.-1 valency
What is the oxidation number of each ion in the compound MgBr2?
In MgBr2, the magnesium ion (Mg) has an oxidation number of +2, while the bromide ion (Br) has an oxidation number of -1.
What is the oxidation no Of S In s4o6-2?
To determine the oxidation number of sulfur (S) in the polyatomic ion S4O6^2-, we can set up an equation where the sum of the oxidation numbers equals the charge of the ion. In this case, the total charge is -2. Each oxygen atom has an oxidation number of -2, so the total oxidation number contributed by oxygen is -12. To solve for sulfur, we set up the equation: 4x + 6(-2) = -2, where x is the oxidation number of sulfur. By solving this equation, we find that the oxidation number of sulfur in S4O6^2- is +5.
What is the charge of chlorate ion?
The charge of the chlorate ion is -1.
What is the oxidation number of CO3?
The oxidation number of carbonate ion (CO3) is -2. Each oxygen atom has an oxidation number of -2, and the sum of the oxidation numbers in the ion must equal the charge of the ion, which is -2.
What is the oxidation number of nitrito?
The oxidation number of the nitrite ion (NO2-) is -1. The oxidation number of nitrogen in the nitrite ion is +3, and each oxygen atom has an oxidation number of -2.
What is chemical formula for the chlorite ion?
The chemical formula for chlorite ion is ClO2- and the other oxy-anions of chlorine are (IUPAC names in parentheses); ClO- : Hypochlorite ion [ Chlorate(I) ion ] ClO3- : Chlorate ion [ Chlorate(V) ion ] ClO4- : Perchlorate ion [ Chlorate(VII) ion ]
How does the oxidation number of a monatomic ion compare to its charge?
The oxidation number of a monatomic ion equals its charge. For example, the oxidation number of a sodium ion (Na+) is +1, which matches its charge of +1.
