There are two oxidation numbers. P shows +5 oxidation number.
The oxidation number of P2O5 is Phisphorus +5, Oxygen -2.
-3. The sum of oxidation numbers of the atoms in all polyatomic ion is the net charge - its part of the definition of oxidation number.
sum will be zero
5
The oxidation number of P2O5 is Phisphorus +5, Oxygen -2.
The oxidation number of P2O5 is Phisphorus +5, Oxygen -2.
In a neutral compound, the sum of the oxidation numbers of the atoms in the compound is zero.
-3. The sum of oxidation numbers of the atoms in all polyatomic ion is the net charge - its part of the definition of oxidation number.
sum will be zero
5
Zero
The oxidation number of P2O5 is Phisphorus +5, Oxygen -2.
The correct chemical formula should be P2O5 or P4O10 (its dimer) and not P3O10 (as originally asked in the question). The oxidation numbers are -2 for each O +5 for each P
0.
0 they are neutral
The oxidation number of oxygen in most compounds is -2.
The oxidation numbers of the elements in a chemical formula, some of which will be positive and others of which will be negative, when multiplied by the numbers of atoms with each oxidation number, must produce products that add to a net result of zero.