P is +3, O is -2
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
Zero. Phosphorus will not trade electrons with itself.
In the chemical formula P2O5, there are 2 phosphorus (P) atoms and 5 oxygen (O) atoms. To find the total number of atoms, you simply add these numbers together: 2 + 5 = 7. Therefore, there are a total of 7 atoms in P2O5.
The formula Fe₃P₂ represents iron(II) phosphide. In this compound, iron has a +2 oxidation state, and it combines with phosphorus to form the compound. Iron(II) phosphide is typically used in various applications, including as a semiconductor and in metal alloys.
Molar mass of P2O5 is 142gmol-1. You need 17.2 moles of p.
The oxidation number of P in P2O5 is +5. This is because oxygen typically has an oxidation number of -2, and there are 5 oxygen atoms in P2O5. The sum of the oxidation numbers in a neutral compound must equal zero, so the oxidation number of P is calculated as +5.
The sum of the oxidation numbers for P2O5 is zero. In P2O5, the oxidation number for phosphorus is +5, and each oxygen atom has an oxidation number of -2. Since there are five oxygen atoms, the total sum of the oxidation numbers is 2(+5) + 5(-2) = 0.
The oxidation number of P2O5 is Phisphorus +5, Oxygen -2.
The correct chemical formula should be P2O5 or P4O10 (its dimer) and not P3O10 (as originally asked in the question). The oxidation numbers are -2 for each O +5 for each P
The formula for the compound containing Ga and P is GaP. This is because the oxidation state of Ga is +3, and the oxidation state of P is -3. By combining one atom of Ga with one atom of P, they balance each other out to form a neutral compound.
P is phosphorus, O is oxygen P2O5 molecules have two (di-) P atoms, and five (pent-) O atoms, so the name of the compound is diphosphorus pentoxide.
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
The structural formula of P2O5 is O=P(O)OP(=O)O, where the central phosphorus atom is bonded to four oxygen atoms through double bonds. The molecule has a cage-like structure with a central P-O-P bridge.
To convert PO4-P to P2O5, you can use the molar mass of each compound. Phosphorus (P) has a molar mass of 30.97 g/mol, while P2O5 has a molar mass of 141.94 g/mol. So, you can calculate the conversion factor by dividing the molar mass of P2O5 by the molar mass of P to determine how much P2O5 is equivalent to 1 unit of PO4-P.
In Mg2P2O7, magnesium (Mg) has an oxidation state of +2, phosphorus (P) has an oxidation state of +5, and oxygen (O) has an oxidation state of -2. The sum of the oxidation states for each element in the compound must equal zero due to its neutrality.
Zero. Phosphorus will not trade electrons with itself.
The oxidation state of phosphorus (P) in PCl5 is +5. Each chlorine atom has an oxidation state of -1, and since there are 5 chlorine atoms in PCl5, the total charge contributed by chlorine is -5. To balance this, the oxidation state of phosphorus must be +5.