P is +3, O is -2
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
Zero. Phosphorus will not trade electrons with itself.
In the chemical formula P2O5, there are 2 phosphorus (P) atoms and 5 oxygen (O) atoms. To find the total number of atoms, you simply add these numbers together: 2 + 5 = 7. Therefore, there are a total of 7 atoms in P2O5.
The formula Fe₃P₂ represents iron(II) phosphide. In this compound, iron has a +2 oxidation state, and it combines with phosphorus to form the compound. Iron(II) phosphide is typically used in various applications, including as a semiconductor and in metal alloys.
Molar mass of P2O5 is 142gmol-1. You need 17.2 moles of p.
The oxidation number of P in P2O5 is +5. This is because oxygen typically has an oxidation number of -2, and there are 5 oxygen atoms in P2O5. The sum of the oxidation numbers in a neutral compound must equal zero, so the oxidation number of P is calculated as +5.
The sum of the oxidation numbers for P2O5 is zero. In P2O5, the oxidation number for phosphorus is +5, and each oxygen atom has an oxidation number of -2. Since there are five oxygen atoms, the total sum of the oxidation numbers is 2(+5) + 5(-2) = 0.
The oxidation number of P2O5 is Phisphorus +5, Oxygen -2.
The correct chemical formula should be P2O5 or P4O10 (its dimer) and not P3O10 (as originally asked in the question). The oxidation numbers are -2 for each O +5 for each P
The formula for the compound containing Ga and P is GaP. This is because the oxidation state of Ga is +3, and the oxidation state of P is -3. By combining one atom of Ga with one atom of P, they balance each other out to form a neutral compound.
P is phosphorus, O is oxygen P2O5 molecules have two (di-) P atoms, and five (pent-) O atoms, so the name of the compound is diphosphorus pentoxide.
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
The structural formula of P2O5 is O=P(O)OP(=O)O, where the central phosphorus atom is bonded to four oxygen atoms through double bonds. The molecule has a cage-like structure with a central P-O-P bridge.
To convert PO4-P to P2O5, you can use the molar mass of each compound. Phosphorus (P) has a molar mass of 30.97 g/mol, while P2O5 has a molar mass of 141.94 g/mol. So, you can calculate the conversion factor by dividing the molar mass of P2O5 by the molar mass of P to determine how much P2O5 is equivalent to 1 unit of PO4-P.
Zero. Phosphorus will not trade electrons with itself.
In Mg2P2O7, magnesium (Mg) has an oxidation state of +2, phosphorus (P) has an oxidation state of +5, and oxygen (O) has an oxidation state of -2. The sum of the oxidation states for each element in the compound must equal zero due to its neutrality.
Are you thinking of a phosphorus oxide (PO) or elemental metal polonium 'Po'. ???? If you are thinking of an oxide of phosphorus , then the chemical formula is P2O5, or its dimer P4O10; (PO) does NOT exist . If you are thinking of the elemental metal polonium , then the chemical symbol is 'Po'. Note the small case 'o'. Polonium is a highly radio-active and poisonous metal, and is kept in a very secure environment.