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Their sum is 4.
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∙ 11y ago
Jordin Castillo
X²+4x+5=0
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Which equation has the solution set 1 and 3?
The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0
How do you solve the limit as x approaches zero of 1 over x minus 4 plus 1 over x plus 4 all over x?
Limx→0 [ 1 / (x - 4) + 1 / (x + 4) ] / x = Limx→0 1 / (x2 - 4x) + 1 / (x2 + 4x) = Limx→0 (x2 + 4x) / (x4 - 16x2) + (x2 - 4x) / (x4 - 16x2) = Limx→0 (x2 + 4x - 4x + x2) / (x4 - 16x2) = Limx→0 2x2 / (x4 - 16x2) = Limx→0 2 / (x2 - 16) = 2 / (0 - 16) = -1/8
How do you solve for the problem x squared minus 10 equals 4x plus 11?
x2-10 = 4x+11 x2-4x-10-11 = 0 x2-4x-21 = 0 (x+3)(x-7) = 0 x = -3 and x = 7
How do you find the sum of the roots of the equation x2 plus 5x plus 9 equals 0?
This quadratic equation has no real roots because its discriminant is less than zero.
Which equation has imaginary roots a.x2-1 equals 0 b.x2-2 equals 0 c.x2 plus x plus 1 equals 0 d.x2-x-1 equals 0?
To find which has imaginary roots, use the discriminant of the quadratic formula (b2 - 4ac) and see if it's less than 0. (The quadratic formula corresponds to general form of a quadratic equation, y = ax2 + bx + c)A) x2 - 1 = 0= 0 - 4(1)(-1) = 4Therefore, the roots are not imaginary.B) x2 - 2 = 0= 0 - 4(1)(-2) = 8Therefore, the roots are not imaginary.C) x2 + x + 1 = 0= 1 - 4(1)(1) = -3Therefore, the roots are imaginary.D) x2 - x - 1 = 0= 1 - 4(1)(-1) = 5Therefore, the roots are not imaginary.The equation x2 + x + 1 = 0 has imaginary roots.
What are the coordinates of the roots of x2 plus 4x equals 0?
x2 + 4x = 0 ⇒ x(x + 4) = 0 ⇒ x = 0 or x = -4
What is the number and type of roots of the equation x2-4x-32 equals 0?
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
What are the roots of the quadratic equation x2 - 4x plus 4 equals 0?
x2-4x+4 = 0 (x-2)(x-2) = 0 x = 2 or x = 2 It has two equal roots.
What is x2 plus 4x plus 4 equals 25?
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
If the sum of the roots of x2 3x-5x0 is added to the product of the roots?
Um, x2+3x-5=0? This is ax2+bx+c where a=1, b=3, and c=-5. The sum of the roots is -b/a so that means the sum of the roots is -3. Also, product of the roots is c/a. That means the product of the roots is -5. -3+(-5)= -8. There you have it.
Solve x2 - 4x - 9 equals 0 by completing the square?
x2 - 4x - 9 = 0 ∴ x2 - 4x = 9 ∴ x2 - 4x + 4 = 13 ∴ (x - 2)2 = 13 ∴ x - 2 = ±√13 ∴ x = 2 ± √13
What is the solution of x2-4x-12 is less than 0?
First consider the auxiliary equation x2 - 4x - 12 = 0 This simplifies to (x + 2)(x - 6) = 0 which has root x = -2 and x = 6 Since the coefficient of x2 is positive, the inequality is satisfied between the roots that is, -2 < x < 6
X2 - 4x equals -4?
x2 - 4x + 4 = 0 (x - 2)(x - 2) = 0 x = 2
2x equals x2 plus 4x-3?
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
Which equation has the solution set 1 and 3?
The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0
How do you solve the limit as x approaches zero of 1 over x minus 4 plus 1 over x plus 4 all over x?
Limx→0 [ 1 / (x - 4) + 1 / (x + 4) ] / x = Limx→0 1 / (x2 - 4x) + 1 / (x2 + 4x) = Limx→0 (x2 + 4x) / (x4 - 16x2) + (x2 - 4x) / (x4 - 16x2) = Limx→0 (x2 + 4x - 4x + x2) / (x4 - 16x2) = Limx→0 2x2 / (x4 - 16x2) = Limx→0 2 / (x2 - 16) = 2 / (0 - 16) = -1/8
How do you solve for the problem x squared minus 10 equals 4x plus 11?
x2-10 = 4x+11 x2-4x-10-11 = 0 x2-4x-21 = 0 (x+3)(x-7) = 0 x = -3 and x = 7
