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If the sum of the squares of the vector's components is ' 1 ',then the vector's magnitude is ' 1 '.
Vector magnitude is represented by the square root of the sum of the squares of the independent vector comonents; |V| = (x2 + y2 + z2)1/2.
No. Vectors add at rightangle bythe pythagoran theorem: resultant sum = square root of (vector 1 squared + vector 2 squared)
It is not possible to obtain a vector with a magnitude of 7 when adding vectors of magnitude 3 and 4. The resultant magnitude will be between 1 and 7, as the triangle inequality states that the magnitude of the sum of two vectors is less than or equal to the sum of their magnitudes.
1
It is a vector whose magnitude is 1.It is a vector whose magnitude is 1.It is a vector whose magnitude is 1.It is a vector whose magnitude is 1.
No, the vector (I j k) is not a unit vector. In the context of unit vectors, a unit vector has a magnitude of 1. The vector (I j k) does not have a magnitude of 1.
A unit vector is a vector with a magnitude of 1, while a unit basis vector is a vector that is part of a set of vectors that form a basis for a vector space and has a magnitude of 1.
The unit vector is a vector whose magnitude is 1.
False.
Kinetic Energy, which is: KE = 1/2mv^2 or the kinetic energy is equal to one half the sum of the mass and the square of the velocity Answer2: Energy is a quaternion quantity with a scalar/potential and a vector component. The vector component is mcV. Physics does not recognize vector energy. Kinetic energy is rightfully the vector energy mcV, not a scalar energy, 1/2 mv^2.
Kinetic Energy, which is: KE = 1/2mv^2 or the kinetic energy is equal to one half the sum of the mass and the square of the velocity Answer2: Energy is a quaternion quantity with a scalar/potential and a vector component. The vector component is mcV. Physics does not recognize vector energy. Kinetic energy is rightfully the vector energy mcV, not a scalar energy, 1/2 mv^2.