What is the surface area of the Louvre pyramid?

Answer 1

The Great Pyramid of Giza in Egypt originally stood at a height of 481 feet and had a square base that was 754 feet on one side. With this information and a little bit of calculation, it is easy to find the original surface area of the pyramid (before erosion). The original surface area was approximately 1,490,054.8 ft2.

Here are my calculations:

S=1/2lP+B

P=4s

P=4(754)

P=3,016 ft

So now S=1/2l(3,016)+B

B=s2

B=7542

B=568,516 ft2

Revise and find that S=1/2l(3,016)+568,516 ft2

Now, all we need is the slant height (l). To do this, we must use the Pythagorean Theorem.

A2+B2=C2

3772+4812=l2

142,129+231,361=l2

373,490=l2

l≈611.1 ft

S≈1/2(611.1)(3,016)+568,516

S≈1,490,054.8 ft2